Java object-oriented-method overloading
The so-called method of overloading,
There are two or more methods of the same name in the class, but there is at least one difference in the number, type, and order of the methods, at which time the Bureau forms the overloaded method;
On the code:
1 Packagecom.java1234.chap03.sec03;2 3 Public classDemo01 {4 5 intAddintAintb) {6System.out.println ("Method One"));7 returnA +b;8 }9 Ten /** One * method overloads, number of arguments are not the same A * @parama - * @paramb - * @paramC the * @return - */ - intAddintAintBintc) { -System.out.println ("Method Two"); + returna+b+C; - } + A /** at * Overloading of methods, different types of parameters - * @parama - * @paramb - * @return - */ - intAddinta,string B) { inSystem.out.println ("Method three"); - returnA +Integer.parseint (b); to } + - /** the * The number of parameter types is the same, the return value type is not overloaded, direct error, said method duplicate name * * @paramargs $ */Panax Notoginseng /*long Add (int a,int b) { - return a+b; the }*/ + A Public Static voidMain (string[] args) { theDemo01 demo=NewDemo01 (); +System.out.println (Demo.add (1, 2)); -System.out.println (Demo.add (1, 2,3)); $System.out.println (Demo.add (1, "3")); $ } -}
Operation Result:
Method One
3
Method Two
6
Method Three
4
Here's a note. If the number of parameters and type, the return value is not the same, can not be overloaded, is directly a compilation error, the compiler thinks the method is duplicated.
Specific reasons: we give the following example code:
1 Packagecom.java1234.chap03.sec03;2 3 Public classDemo01 {4 5 intAddintAintb) {6System.out.println ("Method One"));7 returnA +b;8 }9 Ten /** One * The number of parameter types is the same, the return value type is not overloaded, direct error, said method duplicate name A * @paramargs - */ - LongAddintAintb) { the returnA +b; - } - - Public Static voidMain (string[] args) { +Demo01 demo=NewDemo01 (); - intM=demo.add (1, 2);//call a method that returns a value of type int + LongN=demo.add (1, 2);//calling the return value is a long type method A atDemo.add (1, 2);//If such a compiler fainted, would you like to call a method that returns a value of type int or long ? - - } -}
If the calling method specifies a return value type, we can determine if the call is a method, such as int m=demo.add, because the return value m is the int type that certainly
called int add (int a,int b) {method long N=demo.add (1, 2) because the return value n is a long type, that must be called long add (int A,int b) {method
However, if the direct demo.add (); The compiler is a SB, you TM is the method that calls the return value is the int type, or the return value is a long type method;
Java object-oriented-method overloading