Java Regular Expression application instance code _java

String str = "n1e you v00a?" az$z000 #99 9900 Squint 2_ Qiao S3 you y4@ good?! 6 help you d75a8t ";
Pattern p= pattern.compile ("[\u4e00-\u9fa5]")//to intercept Chinese characters.
Matcher m= p.matcher (str);
while (M.find ()) {
System.out.print (M.group ());
}

String str = "n1e you v00a?" az$z000 #99 9900 Squint 2_ Qiao S3 you y4@ good?! 6 help you d75a8t ";
String a = "";
String B = "";
String d = "";
String s = "";
for (int i = 0;i<str.length (); i++) {
char C = Str.charat (i);
if (48<=c && c<=58) {
A+=c;
else if (64<=c && c<=91) {
B+=c;
}else if (96<=c && c<=123) {
B+=c;
}else{
if ((String.valueof (c)). GetBytes (). Length) >1) {
D+=c;
}else{
S+=c;
}
}

}
System.out.println (a);
System.out.println (b);
System.out.println (d);
System.out.println (s);