Java Socket Client

A socket server was made with tornado. But the staff of the joint adjustment is not on the docking.

So the following demo

Import Java.io.*;import java.net.*;p ublic class sockettest{Sockettest () {} void Test () {try{S            Ocket requestsocket = new Socket ("xxx.xxx.xxx.xxx", 60006);            OutputStream out = Requestsocket.getoutputstream ();            InputStream in = Requestsocket.getinputstream ();            byte[] bb = new BYTE[16];            for (int i =0;i<13;i++) {bb[i+3]= (byte) ((int) ' a ' +i);            } bb[0]= (byte) 0x00;            Bb[1]= (byte) 0x0e;            Bb[2]= (byte) 0xaa;            Bb[15]= (byte) 0xFE;                        System.out.println ("client>" +new String (BB));            Out.write (BB);            Out.flush ();            byte[] buffer = new byte[1024];            In.read (buffer);            String responsestr = new string (buffer);            System.out.println ("server>" +responsestr);            Out.close ();            In.close ();        Requestsocket.close ();    } catch (IOException IOException) {        Ioexception.printstacktrace ();        }//catch (ClassNotFoundException Classnot) {//System.err.println ("Data received in unknown format");        }} public static void Main (String args[]) {sockettest client = new Sockettest ();    Client.test (); }}

Both:

1. Details of the compilation execution under Linux:

Javac Sockettest.java

Java sockettest (Do not Java Sockettest.class, or a lot of misleading add trouble)

2. Byte operation, in Java with a byte array, do not worry (128~255) overflow. You can assign values directly.

byte B = (byte) 254;

3. Get the original input and output stream from the socket, and do not use other packages, otherwise there will be strange things.

OutputStream out = Requestsocket.getoutputstream ();

InputStream in = Requestsocket.getinputstream ();

Java Socket Client