Learn point C language (22): Data type

1. About the first address of the array:

#include <stdio.h>
int main (void)
{
    Char Cs[2][3] = {
                      {' A ', ' B ', ' C '},
                      {' D ', ' E ', ' F '}
                    };
    Char *P1,*P2,*P3,*P4;
    P1 = P2 = P3 = P4 = NULL;
    /* The following four pointers are pointing to the same address * *
    P1 = &cs[0][0]; * * This best understanding * *
    P2 = &cs[0];
    P3 = &cs;
    P4 = CS;        * This is the most convenient   * *
    printf ("%p\n%p\n%p\n%p\n", p1, P2, p3, p4);    /* Display Address * *
    printf ("\n%c%c%c\n", *p1, *p2, *P3, *P4); /* Display Content * *
    GetChar ();
    return 0;
}

2. The address of other elements of the array:

In the example, the elements of an array should be arranged in memory in this way:

[0] [0] [0][1] [0][2] [1][0] [1][1] [1][2]

The following is the way to get the third element of an array by pointer:

#include　<stdio.h>

int　main(void)
{
　　int　nums[2][3]　=　{
　　　　　　　　　　　　{11,12,13},
　　　　　　　　　　　　{21,22,23}
　　　　　　　　　　　};
　　int　*p1,*p2;
　　p1　=　p2　=　NULL;

　　p1　=　&nums[0][2];

　　p2　=　nums;
　　p2　=　p2　+　2;
//　　p2　=　(int　*)nums　+　2;　/*　或者用这一句替换上面两行　*/

　　printf("%d,%d\n",*p1,*p2);

　　getchar();
　　return　0;
}