New? Dynamically allocate array space?. Xml

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?? (i) define an integer?????????????
   
    Int?*
    
     P?
     
      =
      
       New?
       
        Int;????????
        
         Int?*
         
          P?
          
           =
           
            New?
            
             Int
             
              (
              
               4
               
                );? Assigning an initial value
                
                 4?? (ii) Define a one-dimensional array?????????????????
                 
                  Int?*
                  
                   P?
                   
                    =
                    
                     New?
                     
                      
                       int[ 
                       
                        SIZE];????????? 
                        
                         p? points to the first address of the array, which is the 
                         
                          base unit of type int, and 
                          
                           p is used as the array name?? (iii) Define a two-dimensional array?????? 
                           
                            int 
                            
                             (* 
                             
                              p 
                              
                               ) [ 
                               
                                column]= 
                                
                                 New? 
                                 
                                  int? [ 
                                  
                                   size][ 
                                   
                                    Column]???????????? 
                                    
                                   
                                  
                                 
                                
                               
                              
                             
                            
                           
                          
                         
                        
                      
                     
                    
                   
                  
                 
                
               
              
             
            
           
          
         
        
       
      
     
    
   

First define a pointer (*p) [Column], which indicates that the pointer is in size? column int type? The space is the basic unit, and the new?int[size behind] ... To open up a size space

?

? The first pointer represents a pointer unit in the first two cases???????????? The second pointer represents the pointer element in the case of a two-dimensional array, so that when a two-dimensional array, the pointer is
   
    Column? A
    
     IntThe size of the space is a basic unit of the???????????????
     
      P[
      
       0][
       
        0]? indicates that the first
        
         0Such a basic unit.
         
          0The value of an element??????????
          
           P[
           
            1][
            
             0]? indicates that the first
             
              1Such a basic unit.
              
               0The value of an element????????? Therefore, declaring a two-dimensional array pointer?????????????????
               
                Int?
                
                 (*
                 
                  P
                  
                   
                    ) [ 
                    
                     column];//? 
                     
                      p points to the [ 
                      
                       column] structure, and the [ 
                       
                        column] structure is the 
                        
                         ???????? of the base unit of type int Similarly, three-dimensional arrays can be defined as follows:??????????????? 
                         
                          int? 
                          
                           (* 
                           
                            p 
                            
                             ) [column_1][column_2]= 
                             
                              new? 
                              
                               int? [ 
                               
                                size][column_1][column_2]
                                
                               
                              
                             
                            
                           
                          
                         
                        
                       
                      
                     
                   
                  
                 
                
               
              
             
            
           
          
         
        
       
      
     
    
   

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New? Dynamically allocate array space?. XML