New Ket Practice Game 15 Jim's op-

Time limit: C/s 1 sec, other languages 2 seconds
Space limitations: C/C + + 262144K, other languages 524288K
64bit IO Format:%lld
Title DescriptionWhen Jim brushes the cattle to practice game B. Maze, in order to record the two-dimensional maze, each step can walk in the four direction of displacement, write the code contains the following paragraphs:

int offset[4][2] = {(1, 0), (0, 1), (-1, 0), (0,-1)};

Sharp-eyed readers should quickly find out what's wrong with this code. XD Correct wording should be as follows:

int offset[4][2] = {{1, 0}, {0, 1}, {-1, 0}, {0,-1}};

Jim accidentally punched the curly brace into parentheses so the actual four displacement is recorded as: (0,1), (0,-1), (0,0), (0,0) After this experience, Jim knew that the original comma (comma) is a C + + operator (operator).
Jim began to wonder, to give you a number, parentheses, commas, a valid formula, can quickly get the result of this calculation. Please help Jim write a procedure for calculating this kind of calculation. 〜note: People unfamiliar with the comma operator can refer to cppreference.com.
The following also gives a simple definition of the comma operator: (If you are not careful with C + + regulations, please take the following four): 1. For all integers that satisfy-2 31≤x≤2 31-1, x itself is a valid expression, and the value of this expression is that number. (if x is not 0, the number part cannot start with 0, if 0, it must just be a 0.)
2. If e 1,e 2,...,e n is a valid expression, then E 1,e 2,...,e n is also a valid expression, and its value is the value of e N.
3. If e is a valid expression, then (e) is also a valid expression with the value of E.
It is illegal to use an expression that is not available in the relationship of the above-quoted items.
For example, 514,1,2, ( -2147483648,2,4), (((0)), (1), (2) are all valid expressions in this question, but 0514,-02, (), (23,43)) are illegal.

Input Description:

Enter only one row, containing a string E, which is a legal expression consisting of only the left and right parentheses ' (', ') ', comma ', ', and Integer.

Output Description:

The output line contains an integer that represents the result of the operation of the input supplied expression.

Example 1 input

(5,-14)

Output

-14

Example 2 input

((406, (0,2147483647,-2147483648)))

Output

-2147483648

remark:

the range of all integers in 1≤|e|≤100 e is -231≤x≤231-1

e satisfies the legal expression referred to in note, with special emphasis, E does not contain "(space)

#include <bits/stdc++.h>
using namespace std;
int main () {
    string s;
    cin>>s;
    int len=s.length ();
    if (len<=2) {for
        (int i=0;i<len;i++) cout<<s[i];
        cout<<endl;
        
    }
    else{
    int vis=0;
    for (int i=len-1;i>=0;i--) {
        if (s[i]== ', ') {
            vis=i;break;
        }
    }
        
       
    Vector<char> ans;
    for (int i=vis;i<len;i++) {
        if (s[i]>= ' 0 ' &&s[i]<= ' 9 ' | | s[i]== '-') Ans.push_back (S[i]);
        
    }
    
    for (int i=0;i<ans.size (); i++) {
        cout<<ans[i];
    }
    cout<<endl;
    }
}

The comma operation is actually based on the result of the symbolic priority, so as long as the number of the last assignment is found is the result.