Php format timestamp, php format

Php format timestamp, php format

In CMS, it usually takes a few minutes to display a new article with a relatively new display time. A few days ago, this is the case, but generally the database records all timestamps (at least I used to do this ), therefore, we need a conversion process. Based on the information on the Internet, we have added our own modifications and encapsulated two sections of code.

The following is an encapsulated method.

Function formatTime ($ time) {$ time = (int) substr ($ time, 0, 10); $ int = time ()-$ time; $ str = ''; if ($ int <= 2) {$ str = sprintf ('hangzhou', $ int);} elseif ($ int <60) {$ str = sprintf ('% d seconds ago', $ int);} elseif ($ int <3600) {$ str = sprintf ('% d minutes ago ', floor ($ int/60);} elseif ($ int <86400) {$ str = sprintf ('% d h ago', floor ($ int/3600 ));} elseif ($ int <2592000) {$ str = sprintf ('% d days ago', floor ($ int/86400 ));} else {$ str = date ('Y-m-d H: I: s', $ time);} return $ str ;}

Or more detailed

Function formatTime ($ time) {$ text = ''; $ time = intval ($ time); $ ctime = time (); $ t = $ ctime-$ time; // time difference if ($ t <0) {return date ('Y-m-d', $ time) ;}; $ Y = date ('y', $ ctime) -date ('y', $ time); // whether to switch ($ t) {case $ t = 0: $ text = 'new'; break; case $ t <60: // $ text = $ t in one minute. 'Seconds ago '; break; case $ t <3600: // $ text = floor ($ t/60) within an hour ). 'minute ago '; break; case $ t <86400: // $ text = floor ($ t/3600) in a day ). 'hour ago '; // break in a day; case $ t <2592000: // if ($ time> strtotime (date ('ymmd ', strtotime ("-1 day") {$ text = 'Yesterday ';} elseif ($ time> strtotime (date ('ymd ', strtotime ("-2 days") {$ text = 'day before yesterday ';} else {$ text = floor ($ t/86400 ). 'Day before ';} break; case $ t <31536000 & $ y = 0: // not cross-year in a year $ m = date ('M', $ ctime) -date ('m', $ time)-1; if ($ m = 0) {$ text = floor ($ t/86400 ). 'day';} else {$ text = $ m. 'months ago ';} break; case $ t <31536000 & $ y> 0: // cross-year in a year $ text = (11-date ('M ', $ time) + date ('M', $ ctime )). 'months ago '; break; default: $ text = (date ('y', $ ctime)-date ('y', $ time )). 'years ago '; break;} return $ text ;}

Share another similar

// Format the friendly display time function formatTime ($ time) {$ now = time (); $ day = date ('Y-m-d', $ time ); $ today = date ('Y-m-d'); $ dayArr = explode ('-', $ day); $ todayArr = explode ('-', $ today ); // The number of days in the distance. This method is not necessarily accurate if it exceeds 30 days, but it is accurate within 30 days, because a month may be 30 days or 31 days $ days = ($ todayArr [0]-$ dayArr [0]) * 365 + ($ todayArr [1]-$ dayArr [1]) * 30) + ($ todayArr [2]-$ dayArr [2]); // The number of seconds from the distance $ secs = $ now-$ time; if ($ todayArr [0]-$ dayArr [0]> 0 & $ days> 3) {// return date ('Y-m-d', $ time) beyond 3 days across the year;} else {if ($ days <1) {// Today if ($ secs <60) return $ secs. 'Seconds ago '; elseif ($ secs <3600) return floor ($ secs/60 ). "Minutes Ago"; else return floor ($ secs/3600 ). "Hours Ago";} else if ($ days <2) {// Yesterday $ hour = date ('h', $ time); return "yesterday ". $ hour. 'point';} elseif ($ days <3) {// the day before yesterday $ hour = date ('h', $ time); return "the day before yesterday ". $ hour. 'point';} else {// return date ('m month d ', $ time) Three days ago );}}}