Php multi-dimensional array acquisition problem, beginner

{Code...} I want to get array (1, 2, 3, 4, 5); how does the value in this one-dimensional array get it? I got it like this: $ array [0], but it doesn't work. It seems like java and c. Php is a beginner. He is currently trying to switch from the front-end to the backend;

        $array = array(1,2,3,4,5);        $array[0] = array(a,b,c,d,e,f,g);        $array[1] = array(A,B,C,D,E,F,G);       

I want to get array (, 5); how do I get the values in this one-dimensional array?

I got it like this: $ array [0], but it doesn't work. It seems like java and c.

Php is a beginner. He is currently trying to switch from the front-end to the backend;

Reply content:

        $array = array(1,2,3,4,5);        $array[0] = array(a,b,c,d,e,f,g);        $array[1] = array(A,B,C,D,E,F,G);       

I want to get array (, 5); how do I get the values in this one-dimensional array?

I got it like this: $ array [0], but it doesn't work. It seems like java and c.

Php is a beginner. He is currently trying to switch from the front-end to the backend;

var_dump($array);

Click it and you will understand it.

php$array = array(1,2,3,4,5);

When you assign values in this way, it is actually equivalent to array (0 => 1, 1 => 2, 3 => 4, 4 => 5 );
When the key (or subscript) is not specified, it is automatically started and incremented with 0.
Then you assign a value to $ array [0] And the array will become

phparray(0=>array(a,b,c,d,e,f,g), 1=>2, 3=>4, 4=>5);

That is to say, the original 1 has become an array, so the array (, 5) cannot be obtained, because the original value has been changed.
You can write the traversal as follows:

phpforeach($arr as $var) {    print_r($var);}