Python built-in function type () and isinstance () Introduction

Python does not support methods or function overloads, so you have to make sure that you call the function or object you want. What exactly is stored in a name? Quite a lot, especially when this is a type of name. It is often useful to confirm the identity of the type object that is received. To achieve this, Python provides a built-in function, type (). Type () returns the types of any Python object object, not limited to the standard type. Let's look at several examples of using the type () built-in function to return multiple object types through the interactive interpreter:

1>>> Type ("')2<type'Str'>3>>>4>>> s ='XYZ'5>>>type (s)6<type'Str'>7>>>8>>> Type (100)9<type'int'>Ten>>> Type (0+0j) One<type'Complex'> A>>>type (0L) -<type'Long'> ->>> Type (0.0) the<type'float'> ->>> ->>>type ([]) -<type'List'> +>>>type (()) -<type'tuple'> +>>>type ({}) A<type'Dict'> at>>>type (type) -<type'type'> ->>> ->>>classFoo:Pass #New-style class - ... ->>> foo =Foo () in>>>classBar (object):Pass #New-style class - ... to>>> bar =Bar () +>>> ->>>type (Foo) the<type'Classobj'> *>>>type (foo) $<type'instance'>Panax Notoginseng>>>type (Bar) -<type'type'> the>>>type (BAR) +<class '__main__. Bar'>

Python2.2 unifies the types and classes, and if you are using an interpreter below Python2.2, you may see different output results.

1>>> Type ("')2<type'string'>3>>>type (0L)4<type'Long int'>5>>>type ({})6<type'Dictionary'>7>>>type (type)8<type'Builtin_function_or_method'>9>>>Ten>>> type (Foo)#assumes Foo created as in above One<type'class'> A>>> Type (foo)#assumes Foo instantiated also -<type'instance'>

Python built-in function type () and isinstance () Introduction