Python job----Writing login interface

Job Requirements:

1. Enter User name password

2. After the success of the certification show drink information

3. Input error three times after locking

# -*- coding: utf-8 -*-# created by chaimengimport sysretry_limit  = 3  #定义输错次数限制retry_count  = 0   #定义计数器初始值account_file  =  ' Account.txt '    #文件变量定义account_lock  =  ' account_lock.txt '    #文件变量定义while  retry_ count < retry_limit:    #定义循环条件, when the value of the calculator is less than 3 o'clock, has been circulating     file_obj_ Lock = open (Account_lock, "R")    #已只读模式打开account_lock文件     account  = input ("Please enter user name: ")     #提示用户输入用户名     for username in  file_obj_lock.readlines ():   #使用readlines读取account_lock里的锁定账户          if account == username.strip ():    #判断如果输入账户在锁定账户内, then prompt and launch              print ("Your account is locked in the list")            &Nbsp; sys.exit (2)     password = input ("Please enter your password: ")   # Prompt user to enter password     file_obj_account = open (account_file,  "R")   # Opened the account file     match_flag = False    #定义匹配标志位 read-only mode, Determine whether the user name and password are entered correctly according to the matching flag     for line in file_obj_account.readlines ():    #使用readlines读取account里的账户及密码         user,pwd =  Line.strip (). Split ()          #剥去行收尾的空格, then separate the user name and password based on the space between the user name and password. and assigns a value to the USER,PWD variable         if account == user and  password == pwd :  #判断用户名和密码是否相等, if the match is output cue information, and the matching flag position true             print (account +  '   successfully matched ')              match_flag = true            break   # Jump out of this time for loop body     file_obj_account.close ()    #关闭account文件      File_obj_lock.close ()    #关闭account_lock文件     if match_flag ==  false:   #如果匹配标志位为False, the account information error         print ("User name or password error")         retry_count += 1   #计数器加一      else:        print (' Welcome login ')   #否则账号信息正确          break   #用户登录成功, interrupt while loop Else:    print (' Your account is locked! ')     f = open (' Account_lock.txt ', ' a ')     f.write (' \ n '  +  account )    #对输错三次的用户账号进行锁定     f.close ()

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Python job----Writing login interface