Python_ How to quickly find public key in a dictionary

Scenario Example:

Spanish football League, scoring stats for each round of players:

First round: {' 1 ': 1, ' 2 ': 4, ' 5 ': 2, ' 7 ': 3}

First round: {' 2 ': 1, ' 5 ': 4, ' 6 ': 2, ' 3 ': 3}

First round: {' 1 ': 1, ' 4 ': 4, ' 6 ': 2, ' 7 ': 3}

......

Question: Count the first n rounds, the players who scored?

How to solve this problem?

Method 1:

#!/usr/bin/python3from random import Randint, sampledef get_s (player):    # get three-season stochastic record    S1 = {K:randint (1, 6) for K In the sample (Player, Randint (3, 6))}    s2 = {K:randint (1, 6) for K in sample (Player, Randint (3, 6))}    s3 = {K:randint ( 1, 6) for K in sample (Player, Randint (3, 6))}    return s1, S2, S3def public_keys (S1, S2, S3):    # define Intermediate list    median = []        # Judging dictionary public key, in S1, at S2, in S3 must be public key for    key in S1:        if key in S2 and key in S3:            median.append (key)    re Turn medianif __name__ = = ' __main__ ':    # generate ABCDEF player    player = ' abcdef '        # get 3 seasons of random number    S1, s2, s3 = get_s ( Player)        # Gets the player who scored for 3 seasons    result = Public_keys (S1,S2,S3)    print (Result)

Method 2:

The player who scored is the key in the data, by finding the keys for each round and then making the intersection to find the results.

#!/usr/bin/python3from random import Randint, sampledef get_s (player):    # get three-season stochastic record    S1 = {K:randint (1, 6) for K In the sample (Player, Randint (3, 6))}    s2 = {K:randint (1, 6) for K in sample (Player, Randint (3, 6))}    s3 = {K:randint ( 1, 6) for K in sample (Player, Randint (3, 6))}    return s1, S2, S3def public_keys (S1, S2, S3):    # Returns the single-sided value of each dictionary and the intersection, which is the result    return S1.keys () & S2.keys () & S3.keys () if __name__ = = ' __main__ ':    # generate ABCDEF player    player = ' abcdef ' 
   # get 3-season random number    S1, s2, s3 = get_s (player)        # get 3 goals for the players scoring player    result = Public_keys (S1, S2, S3)    print ( Result

Method 3:

        When n rounds, through the map and reduce functions

#!/usr/bin/python3from random import Randint, samplefrom functools Import Reducedef get_s (player): # get Random records for three seasons S1 = {K:randint (1, 6) for K in sample (Player, Randint (3, 6))} s2 = {K:ra Ndint (1, 6) for K in sample (Player, Randint (3, 6))} s3 = {K:randint (1, 6) for K in sample (Player, Randint (3, 6))} R  Eturn s1, S2, S3def public_keys (S1, S2, s3): result = reduce (lambda A, b:a & B, Map (Dict.keys, [S1, S2, S3]) # Map (dict. KEYS,[S1,S2,S3,...... N] Get each round of keys set, S1 ...  N for the Dictionary object # Reduce ((Lamda a,b:a&b,map ()) The collection of map obtained, put in a A, B, return the intersection # A, a = A&b, a value taken out of map (Dict.keys, [S1, S2, S3]) get a new list # The lambda in reduce can only pass in two parameters # Map is a higher order function, receive a map (function, [parameter]), iterate over a parameter list, process in an incoming function, return the processing result into a new list return R        Esultif __name__ = = ' __main__ ': # generate abcdef player player = ' abcdef ' # get 3-season random number S1, s2, s3 = get_s (player) # get a player who scored 3 seasons result = Public_keys (S1, S2, S3) Print (result) 

Python_ How to quickly find public key in a dictionary