If the annual growth rate of GDP of our country is 9%, calculate 10 years after our country's gross domestic product and now compare the percentage of growth%//p = (1 + R) ^n r--Annual growth rate n--years p--vs now multiples # include < Stdio.h> #include <math.h>int main () {double r = 0.09;double P;int n = 10;p = Pow ((1 + R), N);p rintf ("grew after 10 years %f times \ n ", p); return 0;}
Calculation of interest on deposits. There are 1000 yuan, want to save 5 years, according to the following 5 ways to Save://1, one deposit 5 years. 2, the first deposit 2 years, after the expiry of the principal and interest to save 3 years. 3, the first deposit 3 years, after the expiry of the principal and interest to save 2 years. 4, deposit 1-year period, after the expiry of the principal and interest after the 1-year period, the continuous deposit 5 times. 5, deposit current account. Current interest is settled once every quarter. 1-Year periodic interest: 4.14%;//2 periodic interest: 4.68%;//3 periodic interest: 5.4%;//5-year periodic interest: 5.85%;//Demand deposit interest: 0.72%; (demand deposit is settled once per quarter interest)//r--annual interest rate n--deposit years//1 years of this and: P = 1000* (1+r);//n-year principal and interest and: P = 1000* (1+n*r);//n/a 1-year deposit and principal: P = 1000* (1+r) ^n;//current deposit and interest: P = 1000* (1+R/4) ^4n--a quarter of interest and interest and #inclu De <stdio.h> #include <math.h>int main () {double p1,p2,p3,p4,p5;double p0 = 1000.0;double R1 = 0.0414;double R2 = 0.0468;double R3 = 0.054;double R4 = 0.0585;double Huo = 0.0072;P1 = P0 * (1 + 5 * R4);p 2 = (P0 * (1 + 2 * r2)) * (1 + 3 * R3);p 3 = (P0 * (1 + 3 * r3)) * (1 + 2 * r2);p 4 = P0 * POW ((1 + R1), 5);p 5 = p0 * POW (1 + HUO/4 );p rintf ("One deposit 5 years:%f\n", p1);p rintf ("Deposit 2 years, after maturity will be the principal and interest again 3 years:%f\n", p2);p rintf ("Deposit 3 years, after the expiry of the principal and interest again 2 years:%f\n", p3);p rintf ( "Deposit 1 years, after the expiry of the principal and interest to save 1 years, 5 consecutive times:%f\n", p4);p rintf ("Deposit current deposits. Current interest is settled quarterly:%f\n ", p5); return 0;}
Home purchase from the bank loans a sum of D, quasi-this monthly repayment amount is p, the monthly interest rate is r, calculate how many months to pay off. d = 300000 p = 6000 r = 0.01 to the month after the decimal point, second bit rounded//m = log (p/(p-d*r))/log (1+r) #include <stdio.h> #i Nclude <math.h>int Main () {float d = 300000.0;float p = 6000.0;float r = 0.01;float m;m = log (P/(p-d * r))/ Log (1 + R);p rintf ("needs%3.1f month to pay off \", m); return 0;}
Translate "China" into code, password rule: replace the original letter with the 4th letter behind the original letter. Requirements: First assign the initial value, and then respectively with Putchar and printf output # include <stdio.h>int main () {char C1 = ' C '; char c2 = ' h '; char c3 = ' i '; char C4 = ' n ' ; char c5 = ' a '; c1 = c1 + 4;C2 = C2 + 4;c3 = c3 + 4;c4 = c4 + 4;c5 = c5 + 4;printf ("Password is:%c%c%c%c%c\n", c1,c2,c3,c4,c5);p Utch AR (C1);p Utchar (C2);p Utchar (C3);p Utchar (C4);p Utchar (C5);p utchar (' \ n '); return 0;}
Set the circle radius r = 1.5, the cylinder height H = 3, the circumference is long, circle area, sphere surface area, sphere volume, cylinder volume//requirements: With scanf input data, take the decimal point two # # # # # <stdio.h>int Main () {float r,h; float C,s,sq,vq,vz;float pai = 3.1415926;printf ("Please enter circle Radius:"), scanf ("%f", &r);p rintf ("Please enter cylinder High:"); scanf ("%f", &h) ; c = 2 * Pai * r;s = Pai * r * r;sq = 4 * Pai * r * r;vq = (4/3) * Pai * R * r * R;vz = S * h;printf ("Circle circumference:%4.2f\n", c) ;p rintf ("Circle area is:%4.2f\n", s);p rintf ("Sphere surface area is:%4.2f\n", sq);p rintf ("Sphere volume is:%4.2f\n", VQ);p rintf ("Cylinder Volume:%4.2f\n", VZ); return 0;}
"C Language" C programming--Rectification--(chapter III)--2