"SPOJ694" Distinct substrings (SA)

Source: Internet
Author: User

To find the number of different substrings the problem is equivalent to the number of prefixes that are not equal to all suffixes. That is, for each suffix suffix (sa[i]), will contribute n-sa[i]+1, but at the same time, to subtract those duplicates, that is, height[i], the answer is n-sa[i]+1-height[i] cumulative.

Constmaxn=1419;varX,y,rank,sa,h,c:Array[0.. MAXN] oflongint; s:ansistring; t,q,n:longint ;functionMax (x,y:longint): Longint;begin ifX>y ThenExit (x)ElseExit (y);End;functionMin (x,y:longint): Longint;begin ifX<y ThenExit (x)ElseExit (y);End;procedureMake ;varI,j,p,tot:longint;beginP:=1;  whileP<n Do  beginFillchar (C,sizeof (c),0);  fori:=1  toN-p Doy[i]:=rank[i+p];  fori:= n-p+1  toN Doy[i]:=0;  fori:=1  toN DoInc (C[y[i]);  fori:=1  toN DoInc (c[i],c[i-1]);  fori:=1  toN Do    beginSa[c[y[i]]:=i;    Dec (C[y[i]]); End; Fillchar (C,sizeof (c),0);  fori:=1  toN Dox[i]:=Rank[i];  fori:=1  toN DoInc (C[x[i]);  fori:=1  toN DoInc (c[i],c[i-1]);  fori:= NDownto 1  Do    beginY[sa[i]]:=C[x[sa[i]];    Dec (C[x[sa[i]]); End;  fori:=1  toN Dosa[y[i]]:=i; Tot:=1; rank[sa[1]]:=1;  fori:=2  toN Do    begin     if(x[sa[i]]<>x[sa[i-1]])or(x[sa[i]+p]<>x[sa[i-1]+P]) ThenInc (TOT); Rank[sa[i]]:=tot; End; P:=p<<1; End;End;proceduremakeht;varI,j,p:longint;beginh[1]:=0; p:=0;  fori:=1  toN Do  beginP:=max (P-1,0); ifrank[i]=1  Thencontinue; J:=sa[rank[i]-1];  while(i+p<=n) and(j+p<=n) and(S[i+p]=s[j+p]) DoInc (P); H[rank[i]]:=p; End;End;procedureInit;vari,j,tot:longint; ch:char;beginReadln (s); N:=length (s); fori:=1  toN Dox[i]:=Ord (s[i]); Fillchar (C,sizeof (c),0);  fori:=1  toN DoInc (C[x[i]); fori:=1  to  the  DoInc (c[i],c[i-1]);  fori:=1  toN Do  beginSa[c[x[i]]:=i;  Dec (C[x[i]]); End; rank[sa[1]]:=1; tot:=1;  fori:=2  toN Do  begin   ifx[sa[i]]<>x[sa[i-1]] ThenInc (TOT); Rank[sa[i]]:=tot; End; make ; makeht;End;proceduresolve;varAns,i:longint;beginans:=0;  fori:=1  toN DoInc (ans,n-sa[i]+1-H[i]); Writeln (ans);End; Begin readln (t);  forq:=1  toT Do  beginInit;  Solve End; End.

"SPOJ694" Distinct substrings (SA)

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.