The difference between the structure of OPENCV storage image and the structure of PictureBox storage image

During this time, I was doing a pedestrian statistics project based on EMGU, and when I framed the area, I found that there were always problems. Then I wrote a small program test, found the problem in the image matrix scan this piece

The coordinates of the mouse on the PictureBox are

And the EMGU is scanned from the Y direction.

1  for(intx =0; x < grayimage1.width; X + +)2                 {3                      for(inty =0; Y < Grayimage1.height; y++)4                     {5                         if(Imganalysis.isinarea (x, Y, plist))6                         {7                            grayimgdata[y, x, 0] = 0;8                         }9                     }Ten}

1. Capture the frame first with the capture class Emgu

1 New Capture (fileName); 2 frame = capture. Queryframe (); // one frame frame playback

2. Whether the scanning (x, y) point is within the framed area, the gray value of the point within the framed area is set to 0

1Image<gray,byte> GrayImage1 = frame. Convert<gray,byte>();2Byte[,,] Grayimgdata =Grayimage1.data;3              4                  for(intx =0; x < grayimage1.width; X + +)5                 {6                      for(inty =0; Y < Grayimage1.height; y++)7                     {8                         if(Isinarea (x, Y, plist))9                         {Ten                           grayimgdata[y, x, 0] = 0;//Gray value 0 One                         } A                     } -                 } -  thepictureBox1.Image = Grayimage1.bitmap;//effect on the PictureBox -  - //method: A decision algorithm specifically for whether a point exists within a polygon - parameter x, y is the spatial coordinate of the pixel point, plist is the list of points that store the polygon +          Public BOOLIsinarea (floatXfloatY, list<pointf>plist) -         { +             intNcount =plist. Count; A             intNcross =0; at              for(inti =0; I < plist. Count; i++) -             { -PointF P1 =NewPointF (ScaleHeight * plist[i]. X, ScaleWidth *Plist[i]. Y); -PointF P2 =NewPointF (ScaleHeight * plist[(i +1)% ncount]. X, ScaleWidth * plist[(i +1) %Ncount]. Y); -                 if(P1. Y = = P2. Y//p1p2 parallel to Y=p0.y -                     Continue; in  -                 if(Y < Math.min (P1. Y, p2. Y))//the intersection is on the p1p2 extension cord. to                     Continue; +  -                 if(Y >= Math.max (p1. Y, p2. Y))//the intersection is on the p1p2 extension cord. the                     Continue; *  $                 //to find the X-coordinate of the intersection--------------------------------------------------------------Panax Notoginseng  -                 DoubleXcross = (Double) (Y-P1. Y) * (Double) (P2. X-p1. X)/(Double) (P2. Y-p1. Y) +P1. X; the  +                 if(Xcross >x) Ancross++;//only single-sided intersections are counted the             } +  -             //The single -sided intersection is even, points outside the polygon--- $  $             return(Ncross%2==1); -}

3 Demo effect: Correct:

Error:

The difference between the structure of OPENCV storage image and the structure of PictureBox storage image