Simple proof of the principle of the Euclidean method
1.
Analytical:
8251=6105+2146, to be simple, I'm going to use A=b+c to show this.
So there are c=a-b then if there is d|a, and d|b, there must be d|a-b, that is, d|c, (D|a said: D is an approximate of a)
It can be seen that the number of conventions A and B must also be approximate to C.
Now suppose D is the greatest common divisor of a and B, then D must be an approximate number of C, so D is the B,c Convention,
Now it's time to prove that it's greatest common divisor:
2.
Prove:
Because of the a=b+c, so the b,c of the Convention is necessarily an approximate number of a, assuming (b,c) =e, ((b,c) =e said E is B and C greatest common divisor) then there is e|b+c, that is e|a according to "D is b,c convention number" know D|e, and because E
Also, the number of conventions of a, B, e|d, E=d visible (A, b) = (b,c) =d
(This idea is a generalization
,
It becomes the division of the law.)
15/6 The number must be less than 6, will become smaller, and eventually become greatest common divisor.
The principle of the Euclidean method