The value and address of method in Golang

This is a creation in Article, where the information may have evolved or changed.

In Golang, the method of the struct is in the following form:

func (R receivertype) funcName (parameters) (results)

If you want to modify the value of a struct's members, the method is defined when its receivertype must be in struct* form. If Receivertype is a struct, the value of the struct member cannot be changed.

Less nonsense, code validation:

Package Mainimport (    "FMT") type tag struct {    value int32}func (_tag tag) change () {    _tag.value = int32 (987)}ty PE tag2 struct {    value Int32}func (_tag *tag2) Change2 () {    _tag.value = int32 (987)}func main () {    _tag: = new (t AG)    _tag.value = 123     _tag. Change ()    FMT. Println (_tag)    _tag. Change ()    FMT. Println (_tag)    _tag2: = tag2{41}    _tag2. Change2 ()    FMT. Println (_TAG2)    _tag2. Change2 ()    FMT. Println (_TAG2)}

In the main function above, the object _tag in the first piece of code is *tag, but its method change cannot alter its value. In the second code, the object _tag is in the form of *ag, but its method change can alter its value.

If anyone is interested, I will go on to say.

The first parameter of method in Golang is its receivertype, and the method in C-system language such as C + + and its similar language Java is class* this by default. In other words, the method in Golang has a value of two objects and the address of the object, and the C language enforces the address of the object to be passed.

So, you can understand that, right?