typedef void (*pfunction) (void); it's especially good for beginners to learn.

Just saw on the internet, explain the special good, suitable for beginners to learn, master please ignore ...
Turn from: http://blog.csdn.net/zyboy2000/article/details/4202349

(* (Void (*) ()) 0) () equivalent (void (*) ()) 0 ()----reason function is a function-to-pointer way, &fun, fun, *fun, **fun are all the same

Hardware address jumps to 0
(* (Void (*) ()) 0) ();

Preliminary knowledge
Float (*h) ();
Indicates that H is a pointer to a function of the float type of the return value
(Float (*) ())
A type converter that represents a pointer to a function with a float type of return value


Assuming FP is a function pointer, then how to invoke the function that FP points to, the method is invoked as follows:
(*FP) ();

According to People's habitual thinking, then we can write
(*0) ();

The upper type cannot take effect because the operator * must have a pointer for the operand, and the pointer must also be a function pointer. So we have to cast 0 to a function pointer (a pointer to a function with a return value of type void).

Assuming that FP is a float pointer, declare the following
float * FP;

Cast 0 to a float pointer (take the variable FP off)
(float *) 0;

Similar:
Assuming FP is a pointer to a function with a function pointer of type void, it is declared as follows:
void (*FP) ();

Cast 0 to the function pointer (variable FP can be removed)
(Void (*) ()) 0

Finally use (void (*) ()) 0 instead of FP to get the use of the call
(* (Void (*) ()) 0) ();




Use typedef to simplify function pointers
For example:
typedef char * string;

String test= "Hello";

Similar
typedef void (*FUNC) (); So func represents the type of a function pointer

(* (func) 0) ();


Example
Method One:
typedef void (*pfunction) (void);

void Fmi_jump (void)
{
Pfunction Jump;
Jump= (pfunction) (0x80000);
Jump ();

}

Method Two:
((Void (code *) (void)) 0xf400) ();