Use examples to differentiate four types of grammar

Source: Internet
Author: User

Compilation principles: This part of the Chinese method is very important. It is also involved in the soft test. At the beginning, this part of the content is quite messy. I can't even understand the definition, so let alone differentiate them. This is a question, analyze the questions, contact the definitions, and discuss them with the students. The relationship between them is shown in the figure below.

 

 

 

1. Grammar

Grammar G is defined as a four-tuple (VN, VT, P, S)

 

  • Vn: Non-terminator set, usually expressed in uppercase letters
  • Vt: The Terminator set, which is usually expressed by lowercase letters.
  • P: generative set (Rule Set)
  • S: Start symbol (recognition symbol)

 

 

Tip: In the following example, uppercase letters indicate non-Terminator, while lowercase letters indicate Terminator.

 

2.0 grammar (phrase)

Set G = (VN, VT, P, S). If each of its generative α → β is in this structure: α (VN 1_vt) * And contains at least one non-Terminator, while β( VN 1_vt) *, G is a 0-type syntax. Type 0 grammar is the least restrictive of these types of grammar, so we can see at least 0 grammar in the questions.

Type 0 grammar is equivalent to a Turing machine.

 

3.1 grammar (contextual grammar)

It is based on the 0-type grammar. Each α → β has | β |> = | α |. | β | indicates the length of Beta.

The 1-type syntax is equivalent to a Linear Bounded automatic machine.

 

Example: If a-> BA exists, | β | = 2, | α | = 1 meets the requirements of type 1 grammar. Otherwise, AA-> A does not conform to the 1-type syntax.

Special case: α → ε also meets the 1 grammar.

 

4.2 grammar (context-independent grammar)

The type-2 Grammar is based on the type-1 grammar and satisfies that every α → β has α as a non-Terminator. For example, a-> BA meets the requirements of Type 2 Grammar.

The Type 2 syntax is equivalent to the push-down machine.

 

Example: Although AB-> Bab meets the requirements of type 1 grammar, it does not meet the requirements of Type 2 Grammar because its α = AB, while AB is not a non-Terminator. A-> Bab is right.

 

5.3 grammar (regular grammar)

It satisfies the following requirements on the basis of Type 2 Syntax: A → α | α B (right linear) or a → α | B α (left linear ).

The Type-3 syntax is equivalent to finite state automation.

Note: Type 3 grammar can only satisfy the right or left linearity.

Example: A-> A, A-> AB, B-> A, B-> CB, which meets the requirements of Type 3 grammar. However, if the derivation is a-> AB, a-> AB, B-> A, B-> CB or derivation

Is: A-> A, A-> BA, B-> A, B-> CB does not meet the requirements of Type 3 method.

 

I believe you can understand the differences between them through examples.

Use examples to differentiate four types of grammar

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