Using Java, object-oriented encapsulation + inheritance method computation

1. First : Given a line of characters, reverse output this string (space.), such as "AB," (4 CD "Output" DC (, Ba "). ( Requirement: Use object-oriented encapsulation + inheritance )

classbu{PrivateString str;  PublicBu () {} PublicBu (String str) { This. str =str; }     PublicString getstr () {returnstr; }     Public voidsetstr (String str) { This. str =str; }     PublicString GetInfo () {returnstr; }}classRvsextendsBu//responsible for flipping { PublicRvs () {} PublicRvs (String str) {Super(str); }     Public voidm () {Given string, reverse output string
String Temp= ""A new string variable is responsible for receiving the string after the reverse orderChar[] CHS =Super. Getstr (). ToCharArray ();  for(inti = Chs.length-1;i >= 0;i--) {Temp+=Chs[i]; }        Super. SETSTR (temp); }}classOthextendsRvs//remove numbers and spaces { PublicOth () {} PublicOth (String str) {Super(str); }     Public voidm2 () {String temp= ""; Char[] CHS =Super. Getstr (). ToCharArray ();//Remove numbers First for(inti = 0;i < chs.length;i++){            if(Chs[i] >= ' 0 ' && chs[i] <= ' 9 '){                Continue; } temp+=Chs[i]; } temp= Temp.replace ("", "" "); Then go to the space, using the Replace () methodSuper. SETSTR (temp); }}classStatt { Public Static voidMain (string[] args) {//Rvs r = new Rvs ("4m 897ou// "); //r.m (); //System.out.println (R.getinfo ());Oth Oth =NewOth ("4m 897ou//"); OTH.M (); The inverse of the string oth.m2 (); After reverse order, the string is stripped of space and number System.out.println (Oth.getinfo ()); Last output is GetInfo () content}}

2. The second type: Enter the number n, is the odd n becomes 3n+1, is an even number is N/2, after several times such a transformation, will make N into 1, the number of output transformation, and the number of requests is

Remainder by 3 ( Requirements: Using object-oriented encapsulation + inheritance )

Package Com.oracle.acm.prac;class x{private int n;private int count;//Times Public X () {count=0;} public X (int n) {count=0;this.n=n;} public void Changenum () {//if n is odd, then n becomes 3n+1, otherwise it becomes half of N if (n%2!=0) {n=3*n+1;} ELSE{N=N/2;}} public int Getchangecount () {//After several such transformations, it is bound to make N 1. The number of output transformations while (n!=1) {this.changenum (); count++;} return count%3; The required number of times to 3}}public class Demo10 {public static void main (string[] args) {X x=new x (2); System.out.println (X.getchangecount ());}}

/**given a single line of characters, this string is output in reverse order (spaces. Number not output),such as "AB," (4 CD "Output" DC (, Ba "). Requirements: Using object-oriented encapsulation + inheritance */
class Bu{private String str;Public Bu () {}Public Bu (String str) {this.str = str;}Public String Getstr () {return str;}Public void Setstr (String str) {this.str = str;}Public String GetInfo () {return str;}}class Rvs extends Bu{Public Rvs () {}Public Rvs (String str) {super (str);}Public void M () {String temp = "";char[] CHS = SUPER.GETSTR (). ToCharArray ();for (int i = Chs.length-1;i >= 0;i--) {temp + = chs[i];}super.setstr (temp);}}class Oth extends Rvs{Public Oth () {}Public Oth (String str) {super (str);}Public void m2 () {String temp = "";char[] CHS = SUPER.GETSTR (). ToCharArray ();for (int i = 0;i < chs.length;i++) {if (chs[i] >= ' 0 ' && chs[i] <= ' 9 ') {continue;}temp + = chs[i];}temp = Temp.replace ("", "");super.setstr (temp);}}class Statt{Public static void Main (string[] args){//rvs r = new Rvs ("4m 897ou//");//r.m ();//system.out.println (R.getinfo ());Oth Oth = new Oth ("4m 897ou//");oth.m ();oth.m2 ();System.out.println (Oth.getinfo ());
} }

Using Java, object-oriented encapsulation + inheritance method computation