UVa 10370 Above Average (Water ver.)

10370-above Average

Time limit:3.000 seconds

Http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=24&page=show_problem &problem=1311

It is said this 90% of Frosh expect to being above average in their class. You are are to provide a reality check.

The standard input contains an integer C, the number of test cases. C data sets follow. Each data set begins with an integer, n, the number of people in the class (1 <= N <= 1000). N integers follow, separated by spaces or newlines, each giving the final grade (an integer between 0 and) of a Studen T in the class. For each case you are to output a line giving the percentage of students whose grade are above average, rounded to 3 Decima L places.

Sample Input

5
5 of
7,
3
, 3, 9, 100, 99, 98 97, 96 95.

Output for Sample Input

40.000%
57.143%
33.333%
66.667%
55.556%

Complete code:

/*0.012s*/
  
#include <cstdio>
  
int num[1010];
  
int main (void)
{
    int i, T, N, average, count;
    scanf ("%d", &t);
    while (t--)
    {
        scanf ("%d", &n);
        Average = 0;
        for (i = 0; i < n; i++)
        {
            scanf ("%d", &num[i]);
            Average + = Num[i];
        }
        Average/= n;///because it is greater than, so no problem ~
        count = 0;
        for (i = 0; i < n; i++)
            if (Num[i] > average) count++;
        printf ("%.3f%%\n", (double) count/n *);
    return 0;
}

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