Web Data Management (i)

Today on the Web data management, the teacher arranged a simple exercise, the topic is as follows:

　　Question : Consider the following documents:
D1 = I like to watch the sun set with my friend.
D2 = The best Places to Watch the Sunset.
D3 = My friend watches the sun come up.

　　Task : Write a program which can output the document ID given by an input word.

　　Problem-solving ideas (1):

1. Use the Java Constains () method of the String class, where implementation code is not affixed.

Problem-solving ideas (2):

1. Splitting a string into an array of strings

2. Determine if the string array contains the given key word.

public class Exercise1 {public static void main (string[] args) {//1. Convert to an array StringBuilder D1 = new StringBuilder ("I like to Watch the sun set with my friend. "); StringBuilder D2 = new StringBuilder ("The best Places to Watch the Sunset."); StringBuilder d3 = new StringBuilder ("My friend watches the sun come up."); /delete The most later point, split string string[] SD1 = D1.deletecharat (D1.length ()-1). ToString (). Split (""); string[] Sd2 = D2.deletecharat (D2.length ()-1). ToString (). Split (""); string[] sd3 = D3.deletecharat (D3.length ()-1). ToString (). Split ("");//2. Enter the keyword scanner scanner = new Scanner (system.in); System.out.print ("Input key word:"); String Word = Scanner.next (), Boolean isSd1 = Search (SD1, Word), Boolean isSd2 = Search (SD2, Word), Boolean isSd3 = Search (SD 3, Word);//3. Traverse looking for if (isSd1 | | isSd2 | | isSd3) {System.out.print ("the key word" + word + "constains in"); if (isSd1) {System.out.print ("D1");} if (ISSD2) {System.out.print ("D2");} if (isSd3) {System.out.print ("D3");}} else {System.out.println ("notFound ");}} private static Boolean search (string[] str, string word) {Boolean flag = False;for (string string:str) {//Do not take case equality if ( String.equalsignorecase (Word) {return true;}} return flag;}}

problem-solving ideas (3):

1. Use Java Regular Expressions (this is the Reg code the author has found on the Internet)

Import Java.util.scanner;import Java.util.regex.pattern;public class Exercise1 {public static void main (string[] args) { String D1 = "I like to watch the sun set with my friend."; String D2 = "The best Places to Watch the Sunset."; String d3 = "My friend watches the sun come up."; /1. Get input, can be multiple words, space split scanner scanner = new Scanner (system.in); System.out.print ("Input key word:"); StringBuffer word = new StringBuffer (Scanner.nextline ()); Scanner.close ();/** * Constructs regular expressions, ignoring case *. * (keyword1|keyword2| ...). * */string words = word.tostring (). Replace (', ' | ');        StringBuilder reg = new StringBuilder (". * ("). append (words). Append ("). *");                  Pattern pattern = Pattern.compile (reg.tostring (), pattern.case_insensitive); Boolean isSd1 = Pattern.matcher (D1). Matches (); Boolean isSd2 = Pattern.matcher (D2). Matches (); Boolean isSd3 =  Pattern.matcher (D3). matches (); if (isSd1 | | isSd2 | | isSd3) {System.out.print ("the key word" + word + "constains in"); if (ISSD1) {System.out.print ("D1");} if (ISSD2) {System.out.print ("D2");} if (isSd3) {System.out.print ("D3");}} else {System.out.println ("not Found");}}}

　　　　

Web Data Management (i)