What if we store the echo variable content in a variable?

What if we store the echo variable content in a variable? This post was last edited by u011552243 at 20:08:40

Php echo email

Problem background: I want to output a table and send it as content by email.
Problem: add the code first,

 $message = '
 
 

  
  
 
   
 
    
'; $message.= 'Driver: '; $message.= $firstName.' '.$lastName; $message.= '
 
   
 
   
 
    
Date:'.$orderTime.'
 
   
 
  
 
 
 
 

  
  
 
   
 
    
No: 1
 
    
Car'.$truck.':'.' '.$licNum; $message.= '
 
   
 
   
 
    
Kund:'.$customerName.'
 
    
Order:'.$orderNum.'
 
   
 
   
 
    
'; $message.= 'Book number:'.$bookNumPick.'
 
    
Produktnamn:'.$productName.'
 
   
 
   
 
    
Chassi:'; $message.= $tankName.'
 
    
Tank number:'.$chassi.'
 
   
 
   
 
    
Place:'.$locationPick.'
 
    
Place 2:'; $message.= $portCodePick.'
 
   
 
   
 
    
Place 3:'.$locationUnload.'
 
    
Place 4:'; $message.= $timeUnload.'
 
   
 
   
 
    
Place 5:'.$ADRclass.'
 
    
Place 5:'.$weight.'
 
   
 
   
 
    
Place 6:'; $message.= $locationLoad.'
 
    
Place 7:'.$loadTime.'
 
   
 
   
 
    
Place 8:'; $message.= '
 
   
 
   
 
    
'.$info.'
 
   
 
   
 
    
Place 9:'.$outE.'
 
    
Place 10:'.$bookNumOut.'
 
   
 
   
 
    
Place 11:'; $message.= $portCodeOut.'
 
    
 
   
 
  
 
 
'; echo $message."
"; $to = $email; $subject = "Task"; $from = EMAIL; $headers = "From: $from"; echo $headers."
";  mail($to,$subject,$message,$headers);

I used double quotation marks at first. later, to ensure that the content in $ message is kept in double quotation marks, I changed the outer double quotation marks to single quotation marks.

In fact, I want the email content to be the result of echo $ message. However, the mail () function is used to send $ message Directly. The result is:

.... (Omitted, visible $ message ).....

Directly sends the content in $ message instead of the result after echo $ message.
What should I do?
Thank you very much for your convenience.

Reply to discussion (solution)

Problem background: I want to output a table and send it as content by email.
Problem: add the code first,

 $message = '
 
 

  
  
 
   
 
    
'; $message.= 'Driver: '; $message.= $firstName.' '.$lastName; $message.= '
 
   
 
   
 
    
Date:'.$orderTime.'
 
   
 
  
 
 
 
 

  
  
 
   
 
    
No: 1
 
    
Car'.$truck.':'.' '.$licNum; $message.= '
 
   
 
   
 
    
Kund:'.$customerName.'
 
    
Order:'.$orderNum.'
 
   
 
   
 
    
'; $message.= 'Book number:'.$bookNumPick.'
 
    
Produktnamn:'.$productName.'
 
   
 
   
 
    
Chassi:'; $message.= $tankName.'
 
    
Tank number:'.$chassi.'
 
   
 
   
 
    
Place:'.$locationPick.'
 
    
Place 2:'; $message.= $portCodePick.'
 
   
 
   
 
    
Place 3:'.$locationUnload.'
 
    
Place 4:'; $message.= $timeUnload.'
 
   
 
   
 
    
Place 5:'.$ADRclass.'
 
    
Place 5:'.$weight.'
 
   
 
   
 
    
Place 6:'; $message.= $locationLoad.'
 
    
Place 7:'.$loadTime.'
 
   
 
   
 
    
Place 8:'; $message.= '
 
   
 
   
 
    
'.$info.'
 
   
 
   
 
    
Place 9:'.$outE.'
 
    
Place 10:'.$bookNumOut.'
 
   
 
   
 
    
Place 11:'; $message.= $portCodeOut.'
 
    
 
   
 
  
 
 
'; echo $message."
"; $to = $email; $subject = "Task"; $from = EMAIL; $headers = "From: $from"; echo $headers."
";  mail($to,$subject,$message,$headers);

I used double quotation marks at first. later, to ensure that the content in $ message is kept in double quotation marks, I changed the outer double quotation marks to single quotation marks.

In fact, I want the email content to be the result of echo $ message. However, the mail () function is used to send $ message Directly. The result is:

.... (Omitted, visible $ message ).....

Directly sends the content in $ message instead of the result after echo $ message.
What should I do?
Thank you very much for your convenience.

Solved by yourself. $ Headers = "From: $ from". "\ r \ n ";;
$ Headers. = "MIME-Version: 1.0 \ n". "Content-type: text/html; charset = UTF-8 '";
You can. Close the post.