Which hero can tell my brother what is the return value of _call () in PHP?

Which hero can tell me what the return value of __call () in PHP is! ~~
Class my{
Public $name = "My Class";

function __tostring () {
Return $this, name. is an empty class "."
";

}
function __call ($n, $v) {
echo "Method not present:" $n. "
";
echo "error value:", Print_r ($v). "
"; The last side output 1, what is going on.
}
}

$p = new My ();

Echo $p;

$p-No ("first", 6,a);



Here is the result of the run: My class is an empty class
Non-existent method: No
Error value: Array ([0] = = First [1] = 6 [2] + a) 1

Why is there a 1 on the last side??? The solution is not to be thought of! ~~




------Solution--------------------
BOOL Print_r (mixed expression [, bool return])
return value of Print_r

function __call ($n, $v) {
echo "Method not present:" $n. "
";
Print_r ($v);
}
------Solution--------------------
Return parameter. If this parameter is set to True,print_r () will not print the result (this is the default action), but instead return its output
So you can do it.

echo "error value:". Print_r ($v, true). "
"; The last side output 1, what is going on.

------Solution--------------------
You're not the __call method, 1 is the return value of Print_r.
function __call ($n, $v)
{
echo "Method not present:" $n. "
";
echo "error value:";p rint_r ($v); The last side output 1, what is going on.
}
Change it so that it doesn't output 1.

You write the echo "wrong value:". Print_r ($v, true). "
"; This will output the return value

Http://zhidao.baidu.com/question/256918769.html

http://cn2.php.net/print_r/

