C + + Job 5

#include void main () {const int n=10;int i,j,k=0,b[n],m=0,a[n];cout>a[i];} cout0) {for (i=0;i#include void main () {const int n=100;int a[n];int i,j,min,max,n1=0,n2=0,sum=0,number;double Average ;cout>number;cout >a[i];if (a[i]100) {coutmax)

C + + Job 5

Item one, array separation#include using namespace std; int main () { const int n=5; Double score[n],max,min,aver,i;cout>score[i];} Max=min=aver=score[0];for (i=1;imax) max=score[i];else if (score[i]Item 3: Achievements #include using

C + + Job 5

Item two, array selection#include using namespace Std;int main () {int a[10],b[10],i,j,m=0,n=0; bool num; cout>a[i]; for (i=0;iItem four, string#include #include using namespace std; int main () { char str[50]; int i=

C + + Job 5

Item 1: Array separationEnter 10 numbers from the keyboard in the array A, put the odd number in the array B, the even in the array c, and then output separately.#include using namespace Std;int main () {int

C + + Job 5

Item 3-Achievements#include int main () {double G[10],max,min,a=0,b=0,aver,m,n,s[10],t[10];int i,j=0,k=0;cout>g[i]; if (g[i]100) coutmax) Max=g[i];else if (g[i]Item 4-String#include #include using namespace std; int main () { char

C + + Job 5

First, the array is separated. #include using namespace std; int main () { const int n=10;int i,j=0,k=0,a[n],b[n],c[n];cout>a[i];} for (i=0;iTwoarray Selection. #include using namespace std; int main () { const int n=10;int i,j,k=0

C + + Job 5

Array separation#include using namespace Std;int main () {const int n=10;int a[n],b[n],c[n],j=0;cout>a[i];} coutArray Selection#include using namespace Std;int main () {const int n=10;int a[n],b[n],i,j,k=0;cout>a[i];for (i=0;iResults#include using

C + + Job 5

First, sum#include using namespace std; int main () { int a[10],i,sum1=0,sum2=0; cout>a[i]; } for (i=0;i0) sum1=sum1+a[i]; else sum2=sum2+a[i]; }

C + + Job 5

 Item 2: Array selectionEnter 10 numbers from the keyboard in array A, place the number of distinct numbers in the array in array B, such as the value in the a data is 1,2,3,4,2,1; the value in the B array is 3 4#include using namespace Std;int

C + + Job 5

one. String#include #include using namespace std; int main () { char str[50]; int d=0,x=0,y=0,z=0,i=0; cout= ' A ' &&str[i]= ' a ' &&str[i]= ' 0 ' &&str[i]Two. Summation#include int main () { cout>a[i]; if (a[

C + + Job 5

Item 1 Array summation#include using namespace Std;int main () { const int n=5;int a[n]={1,2,3,4,5};int i,sum1=0,sum2=0; for (i=0;i>a[i];if (a[i]>0) {sum1+=a[i];} Else{sum2+=a[i];}} coutItem 3: Achievements#include using namespace Std;int main ()

C + + Job 5

Item 2: Array selection#include using namespace Std;int main () {const int N= 10;    int a[n],b[n],i,j=0,k=0,t=0;     cout>a[i];   }    for (i=0;iItem 4: String#include #include using namespace Std;int main () { char str[50]; int

C + + Fifth experiment--array separation

I. Questions and codes/* File name: Array Separator * by: Liang Zhou * completion date: 5 months * Version number: v1.0 * Description of task and solution method part: process Sequence using an array * input description: Enter 10

Implementation of binary lookup tree (c + +)

#ifndef_hj_stl_bst_h_#define_hj_stl_bst_h_/** author:hujian* time:2016/5/8* discription:this file is about binary search tree.** notice:you should no T use Hjstl_vector in anywhere.* because the hjstl_vector have too much bugs.* it isn't work till

C + + on-machine jobs 5

Item 2: Array selection#include using namespace std; int main () { const int n=10; int a[n],b[n],i,j,d=0,c=0; cout>a[i]; for (i=0;iItem 4: String#include #include using namespace std; int main () {

C + + Job 5

/* Item 2: Array selection */#include void Main () { const int n=10; int A[n];int b[n]={0};int i=0,j=0,n=0; cout>a[i];for (i=0;i/* Project 4: String */# include #include int main () {char str[50];cout= ' 0 ' &&str[i]= ' a ' &&str[i

C + + fifth time job

Item 2: Array selection#include using namespace std; int main () { const int n=10; int a[n],b[n],i,j,k,m=0; cout>a[i]; for (i=0;iItem 4: String#include #include using namespace std; int main () { char str[50]

C + + Fifth experiment-string

I. Questions and codes/ * file name: My c++* : Chen Wanxin * Completion Date: May 8, 2015 * version number: v1.0 * Description of task and solution method part: Count the number of characters by array * Input Description: Enter the words of

C + + fifth time job-string

A problem and code* File Name: String * Creator: Santa Fe * Completion date: 5 months * Version number: v1.0 * Description of the task and solution Method Section: Slightly * Input Description: String * problem stroke READ: Filter

"C # design mode-strategist mode"

I. Strategist mode definition:The policy pattern defines a series of algorithms, encapsulates each algorithm, and allows them to be replaced with each other. The policy pattern makes the algorithm independent of the customers who use it.Two. The

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