Array pointer problems

Array pointer & lt ;? Php $ arr & nbsp ;=& nbsp; array ('id' = & gt; 1, 'title' = & gt; 'test 1 ',), array ('id' = & gt; 2, 'title' = & gt; 'test 2',), array ('id' = & array pointer

 
$ Arr = array (
Array (
'Id' => 1,
'Title' => 'test 1 ',
),
Array (
'Id' => 2,
'Title' => 'test 2 ',
),
Array (
'Id' => 3,
'Title' => 'test 3 ',
),
Array (
'Id' => 4,
'Title' => 'test 4 ',
),
Array (
'Id' => 5,
'Title' => 'test 5 ',
),
);

While (list ($ k, $ v) = each ($ arr )){

Print_r (current ($ arr ));

Echo'
';

}

Loop a two-dimensional array and use current to return the current element. Why does it start with 2nd elements? To learn how to do this from 1, please share with us: 1, 'title' => 'test 1',), array ('id' => 2, 'title' => 'test 2... 'data-pics = ''>
------ Solution --------------------
When you first execute the while (list ($ k, $ v) = each ($ arr) here (note: each -- returns the current key/value pair in the array and moves the array pointer one step forward)
That is to say, each ($ arr) has moved the pointer of $ arr array one by one.
So it starts with 2nd elements.
Let's start with the first one:
Do
{
Print_r (current ($ arr ));
 
Echo'
';
}
While (list ($ k, $ v) = each ($ arr ));

Hope to help you.
------ Solution --------------------
The current function returns the current array unit... During the first while judgment, each has pointed the array unit to the next position .. As a result, the Cup starts from 2.
------ Solution --------------------
Use do instead, because while is the pointer that previously moved one

 $ Arr = array (
Array (
'Id' => 1,
'Title' => 'test 1 ',
),
Array (
'Id' => 2,
'Title' => 'test 2 ',
),
Array (
'Id' => 3,
'Title' => 'test 3 ',
),
Array (
'Id' => 4,
'Title' => 'test 4 ',
),
Array (
'Id' => 5,
'Title' => 'test 5 ',
),
);
Do {

Print_r (current ($ arr ));

Echo'
';
}

While (list ($ k, $ v) = each ($ arr ));



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