Does php use this keyword solution?

Does PHP have the keyword "USE"? I have not read any PHP documents. But when I read a framework, I found that USE is used in it ., I guess not. I don't understand this. & lt ;? Phpnamespacefoo; useMy \ Full \ ClassnameasAnother; // Is there a keyword for using thisisthesameas PHP?
Some PHP documents I have read do not seem to have been used. But when I read a framework, I found that USE is used in it.

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I guess not.
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This is not clear.
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Namespace foo;
Use My \ Full \ Classname as Another;

// This is the same as use My \ Full \ NSname as NSname
Use My \ Full \ NSname;

// Importing a global class
Use ArrayObject;

$ Obj = new namespace \ Another; // instantiates object of class foo \ Another
$ Obj = new Another; // instantiates object of class My \ Full \ Classname
NSname \ subns \ func (); // callfunction My \ Full \ NSname \ subns \ func
$ A = new ArrayObject (array (1); // instantiates object of class ArrayObject
// Without the "use ArrayObject" we wocould instantiate an object of class foo \ ArrayObject
?>
It seems that an alias is defined for a class:

Use class3 as Another;
Use class3 as Another1;
Use class3 as Another2;

$ Obj = new Another ;//
$ Obj = new Another1 ;//
$ Obj = new Another2 ;//

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Php 5.3 +