Php determines whether a user is logged on

To determine whether a user logs in, the first step is to save the data to the session after the user logs in successfully, then, when the user accesses the user permission that needs to be logged on, it determines whether the session is empty. if not, the user logs on successfully. Next, let's look at the instance.

To determine whether a user logs in, the first step is to save the data to the session after the user logs in successfully, then, when the user accesses the user permission that needs to be logged on, it determines whether the session is empty. if not, the user logs on successfully. Next, let's look at the instance.

2. Session_start ();
3.  
4. If (getconfig ("chatroom_admin") == _ post ["username"] & getconfig ("chatroom_adminpassword") = md5 ($ _ post ["password"])
5. {
6. // Log in successfully and register the session
7. Session_register ("administrator ");
8. If (isset ($ _ session ["hack_num"])
9. {
10. Session_unregister ("hack_num ");
11. }
12. $ _ Session ["administrator"] = "yes ";
13. Header ("location: main. php ");
14. Exit;
15. }
16. Else
17. {
18. If ($ _ session ["hack_num"] = "")
19. {
20. Session_register ("hack_num ");
21. $ _ Session ["hack_num"] = 1;
22. }
23. Else
24. {
25. $ _ Session ["hack_num"] ++;
26. }
27. Header ("location:.../notice. php? Id = ". admin_login_lost );
28. Exit;
29. }
30. ?>

When the login is successful, have you registered the code below the session, where the user logs on successfully and saves the data to the session ['hack _ num.

2. // This Page first checks whether the user is logged on correctly. if the user is not logged on, the logon page is displayed.
3. Session_start ();
4. If ((! $ User_id) or (! $ User_array [hack_num]) or (! $ User_array [hack_num]) {
5. Header ("location: login. php3 ");
6. }
7. ?>

The above code is used to determine whether the session ['hack _ num'] has a value. If yes, the logon is successful.