Php uploads an image on the webpage. I want to preview it first. for example, if the uploaded image is displayed on the webpage, what should I do? echo & quot; & lt; imgsrc = '$ tmp_name' & gt; & quot; write like this? How should I write? how can I write a picture after the upload time? & nbsp; & lt ;? Phpif (is _ php uploads images
On the webpage, I want to preview it first. for example, if the picture I just uploaded is displayed on the webpage, what should I do? should I not echo ""; should I write it like this? How to write?
How to rewrite the code by naming the image with the upload time
If (is_uploaded_file ($ _ FILES ['upfile'] ['tmp _ name']) {
Switch ($ type ){
Case 'image/pjpeg ': $ OK = 1;
Break;
Case 'image/jpeg ': $ OK = 1;
Break;
Case 'image/GIF': $ OK = 1;
Break;
Case 'image/png ': $ OK = 1;
Break;
}
If ($ OK & $ error = '0 '){
Move_uploaded_file ($ tmp_name, 'up/'. $ name );
Echo "uploaded successfully ";
Echo "$ name
";
Echo "$ type
";
Echo "$ size
";
Echo "$ tmp_name
";
}
}
?>
------ Solution --------------------
I seem to remember which post you asked this question? I wanted to answer your question this afternoon. Why did you send it here?
What time does your time mean? Timestamp?
Modify here
// Move_uploaded_file ($ tmp_name, 'up/'. $ name );
// Get the file extension
$ Oldname = $ upfile ['name']; // note the inclusion path.
$ Fileexpand = pathinfo ($ oldname, PATHINFO_EXTENSION );
$ Filename = strtotime (); // Time stamp
// $ Filename = date ('ymmdgis '); // Beijing time
Move_uploaded_file ($ tmp_name, 'up/'. $ filename. $ fileexpand );
Here the error is changed
Move_uploaded_file ($ tmp_name, 'up/'. $ filename.'. '. $ fileexpand );
The code above is what you want
How to rewrite the code by naming the image with the upload time
There is another question: Preview the image.
You can use JavaScript to control a hidden div to read the image and assign the file name to js after uploading...
Maybe you cannot understand ....
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