下面小編就為大家帶來一篇淺談C#中List<T>對象的深度拷貝問題。小編覺得挺不錯的,現在就分享給大家,也給大家做個參考。一起跟隨小編過來看看吧
一、List<T>對象中的T是實值型別的情況(int 類型等)
對於實值型別的List直接用以下方法就可以複製:
List<T> oldList = new List<T>(); oldList.Add(..); List<T> newList = new List<T>(oldList);
二、List<T>對象中的T是參考型別的情況(例如自訂的實體類)
1、對於參考型別的List無法用以上方法進行複製,只會複製List中對象的引用,可以用以下擴充方法複製:
static class Extensions { public static IList<T> Clone<T>(this IList<T> listToClone) where T: ICloneable { return listToClone.Select(item => (T)item.Clone()).ToList(); } //當然前題是List中的對象要實現ICloneable介面 }
2、另一種用序列化的方式對引用對象完成深拷貝,此種方法最可靠
public static T Clone<T>(T RealObject) { using (Stream objectStream = new MemoryStream()) { //利用 System.Runtime.Serialization序列化與還原序列化完成引用對象的複製 IFormatter formatter = new BinaryFormatter(); formatter.Serialize(objectStream, RealObject); objectStream.Seek(0, SeekOrigin.Begin); return (T)formatter.Deserialize(objectStream); } }
3、利用System.Xml.Serialization來實現序列化與還原序列化
public static T Clone<T>(T RealObject) { using(Stream stream=new MemoryStream()) { XmlSerializer serializer = new XmlSerializer(typeof(T)); serializer.Serialize(stream, RealObject); stream.Seek(0, SeekOrigin.Begin); return (T)serializer.Deserialize(stream); }}
三、對上述幾種對象深拷貝進行測試
測試如下:
using System;using System.Collections.Generic;using System.Collections ;using System.Linq;using System.Text;using System.IO;using System.Runtime.Serialization;using System.Runtime.Serialization.Formatters.Binary;namespace LINQ{ [Serializable] public class tt { private string name = ""; public string Name { get { return name; } set { name = value; } } private string sex = ""; public string Sex { get { return sex; } set { sex = value; } } } class LINQTest { public static T Clone<T>(T RealObject) { using (Stream objectStream = new MemoryStream()) { IFormatter formatter = new BinaryFormatter(); formatter.Serialize(objectStream, RealObject); objectStream.Seek(0, SeekOrigin.Begin); return (T)formatter.Deserialize(objectStream); } } public static void Main() { List<tt> lsttt = new List<tt>(); tt tt1 = new tt(); tt1.Name = "a1"; tt1.Sex = "20"; lsttt.Add(tt1); List<tt> l333 = new List<tt>(); l333.Add(Clone<tt>(lsttt[0])); l333[0].Name = "333333333"; } }}