Number Steps 代碼語言：c

文章目錄

• Number Steps

Number Steps時限：1000ms 記憶體限制：10000K  總時限：3000ms

描述：

Starting from point (0,0) on a plane, we have written all
non-negative integers 0, 1, 2,... as shown in the figure. For example, 1, 2, and
3 has been written at points (1,1), (2,0), and (3, 1) respectively and this
pattern has continued.

You are to write
a program that reads the coordinates of a point (x, y), and writes the number
(if any) that has been written at that point. (x, y) coordinates in the input
are in the range 0...5000.

輸入：

there is x, and y representing the coordinates (x, y) of a
point.

輸出：

write the number written at that point or write No Number if there
is none.

輸入範例：

4 2
6 6
3 4

輸出範例：

6
12
No Number

提示：

 

來源：

代碼：

1. #include <stdio.h>
2. #include <stdlib.h>
3. int main()
4. {
5. int x,y;
6. scanf("%d%d",&x,&y);
7. if(x%2==0&&y%2==0&&x>=y)
8. printf("%d\n",x+y);
9. else if(x%2!=0&&y%2!=0&&x>=y)
10. printf("%d\n",x+y-1);
11. else
    printf("No Number\n");
12. return 0;
13. }