PHP+MySQL實現的簡單投票系統執行個體

PHP+MySQL實現的簡單投票系統執行個體_php技巧

最後更新：2017-01-19 來源：互聯網

上載者：User

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本文執行個體講述了PHP+MySQL實現的簡單投票系統。分享給大家供大家參考，具體如下：

<html><head><title>手機系統調查問卷</title><style type="text/css"><!--span{  width:600px;  height:100px;  background-color:write;  postion:relative;  border:1px #cccccc solid;}div{  width:60px;  height:1px;  background-color:blue;  postion:absolute;  bottom:0;}--></style></head><body>你現在使用的手機是什麼系統？<form id="form1" method="POST" action="count.php"><input type="radio" name="phone" value="1"> Android安卓<input type="radio" name="phone" value="2"> Symbian塞班<br><input type="radio" name="phone" value="3"> iphone蘋果<input type="radio" name="phone" value="4"> GoogleGoogle<br><input type="radio" name="phone" value="5"> Winphone微軟<input type="radio" name="phone" value="6"> 其它<br><input type="submit" value="提交"></form><span>當前票數：<br><?phpinclude 'connect.php';$sql="select answer from countone";$rs=mysql_query($sql);$total=mysql_num_rows($rs);$sql="select * from countone where answer=1";$rs=mysql_query($sql);$android=mysql_num_rows($rs);$sql="select * from countone where answer=2";$rs=mysql_query($sql);$symbian=mysql_num_rows($rs);$sql="select * from countone where answer=3";$rs=mysql_query($sql);$iphone=mysql_num_rows($rs);$sql="select * from countone where answer=4";$rs=mysql_query($sql);$google=mysql_num_rows($rs);$sql="select * from countone where answer=5";$rs=mysql_query($sql);$winphone=mysql_num_rows($rs);$sql="select * from countone where answer=6";$rs=mysql_query($sql);$other=mysql_num_rows($rs);?><table border="0"><th>android</th><th>Symbian</th><th>iphone</th><th>Google</th><th>winphone</th><th>other</th><tr><td><?php echo $android ?>票</td><td><?php echo $symbian ?>票</td><td><?php echo $iphone ?>票</td><td><?php echo $google ?>票</td><td><?php echo $winphone ?>票</td><td><?php echo $other ?>票</td></tr><tr><td><?php for ($i=1;$i<=$android/$total+1;$i=$i+0.1){  echo "<div></div>"; } ?></td><td><?php for ($i=1;$i<=$symbian/$total+1;$i=$i+0.1){  echo "<div></div>"; } ?></td><td><?php for ($i=1;$i<=$iphone/$total+1;$i=$i+0.1){  echo "<div></div>"; } ?></td><td><?php for ($i=1;$i<=$google/$total+1;$i=$i+0.1){  echo "<div></div>"; } ?></td><td><?php for ($i=1;$i<=$winphone/$total+1;$i=$i+0.1){ echo "<div></div>"; } ?></td><td><?php for ($i=1;$i<=$other/$total+1;$i=$i+0.1){ echo "<div></div>"; } ?></td></tr></table></span></body></html>

寫的有點囉嗦，有點笨但很實用

<?phpinclude 'connect.php';$name=$_POST['phone'];$sql="insert into countone values(null,$name,now(),null)";mysql_query($sql);?><script type="text/javascript"> alert ("投票成功！"); location="question.php";</script>

連結mysql：

<?phpmysql_connect("localhost","root","");mysql_select_db("vote");mysql_query("set names utf8");?>

更多關於PHP相關內容感興趣的讀者可查看本站專題：《php物件導向程式設計入門教程》、《php字串(string)用法總結》、《php+mysql資料庫操作入門教程》及《php常見資料庫操作技巧匯總》

希望本文所述對大家PHP程式設計有所協助。

本文章原先以中文撰寫並發佈於 aliyun.com，亦設英文版本，僅作資訊用途。本網站不對文章的準確性，完整性或可靠性或其任何翻譯作出任何明示或暗示的陳述或保證。如對該文章有任何疑慮或投訴，請傳送電郵至 info-contact@alibabacloud.com 並提供相關疑慮或投訴的詳細說明。職員會於 5 個工作天內與您聯絡，一經驗證之後，即會刪除該侵權內容。

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