[用Golang刷LeetCode之 7] 566. Reshape the Matrix

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題目

In MATLAB, there is a very useful function called 'reshape', which can reshape a matrix into a new one with different size but keep its original data.

You're given a matrix represented by a two-dimensional array, and two positive integers r and c representing the row number and column number of the wanted reshaped matrix, respectively.

The reshaped matrix need to be filled with all the elements of the original matrix in the same row-traversing order as they were.

If the 'reshape' operation with given parameters is possible and legal, output the new reshaped matrix; Otherwise, output the original matrix.

Example 1:

Input:
nums =
[[1,2],
[3,4]]
r = 1, c = 4
Output:
[[1,2,3,4]]
Explanation:
The row-traversing of nums is [1,2,3,4]. The new reshaped matrix is a 1 * 4 matrix, fill it row by row by using the previous list.

Example 2:

Input:
nums =
[[1,2],
[3,4]]
r = 2, c = 4
Output:
[[1,2],
[3,4]]

Explanation:
There is no way to reshape a 2 * 2 matrix to a 2 * 4 matrix. So output the original matrix.
Note:

1. The height and width of the given matrix is in range [1, 100].
2. The given r and c are all positive.

題目大意：

給定二維矩陣nums，將其轉化為r行c列的新矩陣。若無法完成轉化，返回原矩陣。

注意：

給定矩陣的高度和寬度範圍[1, 100]
r和c都是正數

解題思路

1. origin_r * origin_c 的矩陣 reshape為 rc的矩陣，需要滿足：
   origin_r * origin_c=rc
2. 元素位置對應的關係
   如果將矩陣橫向展開為一維數組，元素個數為n=origin_r * origin_c
   在元素在一維數組中對應的位置i：
   原矩陣位置[i/origin_c,i%origin_c]
   新矩陣位置[i/c,i%c]

代碼

reshapeMatrix.go

package _566_Reshape_Matriximport "fmt"func MatrixReshape(nums [][]int, r int, c int) [][]int {    var chanInt chan int    chanInt = make(chan int)    var length int    go func(len *int) {        for _, v1 := range nums {            for _, v := range v1 {                (*len)++                fmt.Printf("len1:%+v\n", length)                chanInt <- v            }        }        for {            chanInt <- 0        }    }(&length)    var ret [][]int    for i := 0; i < r; i++ {        var lineRet []int        for j := 0; j < c; j++ {            v := <- chanInt            lineRet = append(lineRet, v)        }        ret = append(ret, lineRet)    }    fmt.Printf("len2:%+v\n", length)    fmt.Printf("ret:%+v\n", ret)    if r * c != length {        return nums    }    return ret}

測試

reshapeMatrix_test.go

package _566_Reshape_Matriximport "testing"func TestMatrixReshape(t *testing.T) {    input := [][]int{        {1, 2},        {3, 4},    }    ret := MatrixReshape(input, 1, 4)    t.Logf("%+v", ret)}