標籤:Section 1: Essentials of JSF2.0Identify the features of JSF such as Facelets, BookMarkable View, AJAX support and the benefits they bring inIdentify the life cycle stages of JSF, flow of request processing, and purpose of FacesContextDesign XHTML
標籤:JAVA和NET RSA密鑰格式相互轉換(公開金鑰,私密金鑰)不多說直接上代碼,需要引用開源類庫BouncyCastle.Crypto.dll也可以在這裡下載http://downloads.bouncycastle.org/csharp/bccrypto-net-1.7-bin.zip以下為轉化代碼 1 using System; 2 using System.Xml; 3 using Org.BouncyCastle.Asn1.Pkcs; 4 using
標籤:Introduction to Java EEGain an understanding of the Java Platform, Enterprise Edition (Java EE)Examine the Java EE application architectureExamine Java EE container servicesExamine the EJB component typesEvaluate the EJB Lite ContainerCompare
標籤:Application Design Concepts and PrinciplesIdentify the effects of an object-oriented approach to system design including the effect of encapsulation, inheritance, and use of interfaces.Identify how the Separation of Concerns principle applies to
標籤:Section 1: Application Design Concepts and PrinciplesExplain the main advantages of an object-oriented approach to system design including the effect of encapsulation, inheritance, and use of interfaces on architectural characteristics.Describe
標籤:題目Given an integer n, return the number of trailing zeroes in n!.Note: Your solution should be in logarithmic time complexity.分析Note中提示讓用對數的時間複雜度求解,那麼如果粗暴的算出N的階乘然後看末尾0的個數是不可能的。所以仔細分析,N! = 1 * 2 * 3 * ... * N