//計算字串長度(英文佔1個字元,中文漢字佔2個字元)方法一:String.prototype.gblen = function() { var len = 0; for (var i=0; i<this.length; i++) { if (this.charCodeAt(i)>127 || this.charCodeAt(i)==94) { len += 2; } else
由於設計的頁面需要對1280*760和1440*900都有較好的相容性,因此,做了兩個頁,經過一番摸索,終於解決了,小兒科的技巧,高手勿看!<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html
(function(){ var addLarge = function(n1,n2){ var over = 0; var ret = ""; var len = Math.min(n1.length,n2.length); var sln1 = n1.substr(n1.length - len,n1.length ); var sln2 = n2.substr(n2.length - len,n2.length );
(function (){ var addLarge = function(n1,n2){ var carry = 0; var ret = ""; n1=n1.toString(); n2=n2.toString(); var len = Math.min(n1.length,n2.length); var sln1 = n1.substr(n1.length - len,n1.length ); var sln2 =
問題描述:Let d(n) be defined as the sum of proper divisors of n (numbers less than n which divide evenly into n).If d(a) = b and d(b) = a, where a b, then a and b are an amicable pair and each of a and b are called amicable numbers.For example,
var Ann = function a(arr){ if(arr.length == 1){return arr;} var rr = new Array(); for(var i = 0; i<arr.length;i++){ //get a copy var ar = new Array(); for(var j = 0; j < arr.length;j++){ar[j] = arr[j];} //assume
問題描述:In England the currency is made up of pound, , and pence, p, and there are eight coins in general circulation:1p, 2p, 5p, 10p, 20p, 50p, 1 (100p) and 2 (200p).It is possible to make 2 in the following way:11 + 150p + 220p + 15p + 12p + 31pHow
在javascript中,String的函數replace()簡直太讓人喜愛了。它靈活而強大的字元替換處理能力,讓我不禁想向大家介紹它。replace()最簡單的算是能力就是簡單的字元替換。範例程式碼如下:<script language="javascript">var strM = "javascript is a good script language";//在此我想將字母a替換成字母Aalert(strM.replace("