uva 11488 – Hyper Prefix Sets(Trie)

HHyper Prefix SetsPrefix goodness of a set string is length of longest common prefix*number of strings in the set. For example the prefix goodness of the set {000,001,0011} is 6.You are given a set of binary strings. Find the maximum prefix goodness

zoj Information Sharing(並查集)

Information SharingTime Limit: 3 Seconds      Memory Limit: 65536 KBThere is going to be a test in the kindergarten. Since the kids would cry if they get a low score in the test, the teacher has already told every kid some information about the test

hdu Minimum Inversion Number(線段樹求逆序數有關問題的一個小歸納)

Minimum Inversion NumberTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4904    Accepted Submission(s): 2991Problem DescriptionThe inversion number of a given number sequence a1, a2, ..., an is

CF 172(div2) D(單調隊列)

D. Maximum Xor Secondarytime limit per test2 secondsmemory limit per test256 megabytesinputstandard inputoutputstandard outputBike loves looking for the second maximum element in the sequence. The second maximum element in the sequence of distinct

uva 11987 Almost Union-Find(加權並查集)

Problem AAlmost Union-FindI hope you know the beautiful Union-Find structure. In this problem, you're to implement something similar, but not identical.The data structure you need to write is also a collection of disjoint sets, supporting 3

關於floyd的一點 總結

floyd算是求最短路徑裡面的最簡單的一種演算法了。  它一般用在求一個有向網(或無向網),對每一個頂點vi不等於vj,要求求出vi與vj之間的最短路徑和最短路徑的長度。如果用dijkstra的話要迴圈n次,用floyd雖然時間複雜性並未減少,同樣是 o(n^3),但是寫起來更加簡單。這個裡面沒什麼特別好講的地方,值得注意的是他的兩個遞推公式。A^k[i][j]=min{A^(k-1)[i][j],A^(k-1)[i][k]+A^(k-1)[k][j]}

寒假前刷題(7)搜尋系列 dfs hdu 1010

Tempter of the BoneTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 42406    Accepted Submission(s): 11468Problem DescriptionThe doggie found a bone in an ancient maze, which fascinated him a

CF 189 div2 D

D. Psychos in a Linetime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard outputThere are n psychos standing in a line. Each psycho is assigned a unique integer from1 to n. At each step every psycho who has

uva 1428 – Ping pong(樹狀數組)

integers a1, a2...aN follow, indicating the skill rank of each player, in the order of west to east (1ai100000 , i = 1...N ).OutputFor each test case, output a single line contains an integer, the total number of different games.Sample Input13 1 2

poj 2912 並查集

RochambeauTime Limit: 5000MS Memory Limit: 65536KTotal Submissions: 1658 Accepted: 577DescriptionN children are playing Rochambeau (scissors-rock-cloth) game with you. One of them is the judge. The rest children are divided into three groups (it is

CF 154 div2 B(dp)

B. Physics Practicaltime limit per test1 secondmemory limit per test256 megabytesinputinput.txtoutputoutput.txtOne day Vasya was on a physics practical, performing the task on measuring the capacitance. He followed the teacher's advice and did as

uva 12086 – Potentiometers(樹狀數組)

PotentiometersInput: Standard InputOutput: Standard OutputA potentiometer, or potmeter for short, is an electronic device with a variable electric resistance. It has two terminals and some kind of control mechanism (often a dial, a wheel or a slide)

uva 133 救濟金髮放

#include<cstdio>#include<cstring>#include<cstdlib>#include<iostream>using namespace std;int pre[25],next[25];int N,m,n;int pos1,pos2;//移除結點void remove(int n){ next[pre[n]]=next[n];//第二個人的下一個位置

Poj 2082(單調棧)

Terrible SetsTime Limit: 1000MS Memory Limit: 30000KTotal Submissions: 2778 Accepted: 1413DescriptionLet N be the set of all natural numbers {0 , 1 , 2 , . . . }, and R be the set of all real numbers. wi, hi for i = 1 . . . n are some elements in N,

poj 2251 搜尋

Dungeon MasterTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 13923 Accepted: 5424DescriptionYou are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with

hdu 4681 String(dp)

StringTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 0    Accepted Submission(s): 0Problem DescriptionGiven 3 strings A, B, C, find the longest string D which satisfy the following rules:a) D

最簡單的暴力求解演算法 簡單枚舉

題目大意是:輸入正整數n,按從小到大的順序輸出所有形如abcde/fghij=n的運算式,其中a-j恰好為數字0-9的一個排列,2=<n<=79.楊麗輸入:62輸出:79546/01283=6294736/01528=62 //這是一道非常沒含量的簡單的枚舉的題,所以我沒把他算在寒假前刷題裡,之所以把他寫出來是因為這是我第一次真正的開始系統的看關於暴力演算法的東西,暑假的時候打了醬油,現在就是在贖罪,老是聽十元大師說暴力辦法解決這道題,感覺暴力似乎是個很牛逼的東西。今天就寫個最傻逼的

poj 3009 搜尋

Curling 2.0Time Limit: 1000MS Memory Limit: 65536KTotal Submissions: 8582 Accepted: 3603DescriptionOn Planet MM-21, after their Olympic games this year, curling is getting popular. But the rules are somewhat different from ours. The game is played

LA 3644 並查集

X-Plosives A secret service developed a new kind of explosive that attain its volatile property only when a specific association of products occurs. Each product is a mix of two different simple compounds, to which we call a binding pair. If N>2,

poj 1611 並查集

The SuspectsTime Limit: 1000MS Memory Limit: 20000KTotal Submissions: 18435 Accepted: 8920DescriptionSevere acute respiratory syndrome (SARS), an atypical pneumonia of unknown aetiology, was recognized as a global threat in mid-March 2003. To

總頁數: 61357 1 .... 13467 13468 13469 13470 13471 .... 61357 Go to: 前往

聯繫我們

該頁面正文內容均來源於網絡整理,並不代表阿里雲官方的觀點,該頁面所提到的產品和服務也與阿里云無關,如果該頁面內容對您造成了困擾,歡迎寫郵件給我們,收到郵件我們將在5個工作日內處理。

如果您發現本社區中有涉嫌抄襲的內容,歡迎發送郵件至: info-contact@alibabacloud.com 進行舉報並提供相關證據,工作人員會在 5 個工作天內聯絡您,一經查實,本站將立刻刪除涉嫌侵權內容。

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.