10167 – Birthday Cake

描述:我是完全把圓邊緣的點都算出來,放到一個數組裡,然後查詢就可以了#include <iostream>#include <cstdio>#include <cstring>#include <cmath>using namespace std;int num[1010][2],s[100010][2];int main(){ //freopen("a.txt","r",stdin); int n,i,j; for(i=500;

POJ1184 逾時..

聰明的打字員Time Limit: 1000MS Memory Limit: 65536KTotal Submissions: 3647 Accepted: 759Description阿蘭是某機密部門的打字員,她現在接到一個任務:需要在一天之內輸入幾百個長度固定為6的密碼。當然,她希望輸入的過程中敲擊鍵盤的總次數越少越好。 不幸的是,出於保密的需要,該部門用於輸入密碼的鍵盤是特殊設計的,鍵盤上沒有數字鍵,而只有以下六個鍵:Swap0, Swap1, Up, Down, Left, Right,

POJ3624解題報告

Charm BraceletTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 7247 Accepted: 3278DescriptionBessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1

POJ2186解題報告 強連通分支+縮點

Popular CowsTime Limit: 2000MS Memory Limit: 65536KTotal Submissions: 11739 Accepted: 4641DescriptionEvery cow's dream is to become the most popular cow in the herd. In a herd of N (1 <= N <= 10,000) cows, you are given up to M (1 <= M <=

POJ2586解題報告

Y2K Accounting BugTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 4485 Accepted: 2146DescriptionAccounting for Computer Machinists (ACM) has sufferred from the Y2K bug and lost some vital data for preparing annual report for MS Inc. All

POJ3414解題報告 BFS

PotsTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 4638 Accepted: 1965 Special JudgeDescriptionYou are given two pots, having the volume of A and B liters respectively. The following operations can be performed:FILL(i)        fill the pot

POJ2553解題報告 強連通分支

The Bottom of a GraphTime Limit: 3000MS Memory Limit: 65536KTotal Submissions: 4000 Accepted: 1637DescriptionWe will use the following (standard) definitions from graph theory. Let V be a nonempty and finite set, its elements being called vertices

POJ3331解題報告 高精度冪

The Idiot of the Year Contest!Time Limit: 2000MS Memory Limit: 65536KTotal Submissions: 3074 Accepted: 1591DescriptionThere is just one basic rule in the Idiot of the Year Contest (IYC)! The contestant picks a random digit between 0 and 9, computes

Azkaban成功搭建環境的過程

1、先將下載下來2、將壓縮包上傳到hadoop的NameNode上3、用tar xvf azkaban-0.10.tar.gz解壓4、設定HADOOP_HOME環境變數:export HADOOP_HOME=:$HADOOP_HOME:/home/hadoop/azkaban-0.10/test/jobs  為azkaban解壓到的絕對路徑5、進入到azkaban-0.10目錄下:執行ant命令執行ant built-tests命令6、使用以下命令啟動azkaban:bin/azkaban-se

Azkaban的快速搭建

 一、獨立部署通過以下命令來啟動Azkaban:註: 這個部分為絕對路徑然後即可用瀏覽器訪問http://localhost:8081 (若將azkaban部署到伺服器上,則

Ext.form.ComboBox 擷取選中的Value值

直接粘貼代碼:<html xmlns="http://www.w3.org/1999/xhtml"><head runat="server"> <title>ComboxTest</title> <link href="ext-all.css" mce_href="ext-all.css" rel="stylesheet" type="text/css" /> <mce:script src="ext-base-

《大話設計模式》–筆記(單例模式)

單例模式:保證一個類僅有一個執行個體,並提供一個供訪問的全域點。其它優點:單例模式因為是卦裝的它的唯一執行個體,這樣它可以嚴格地控制客戶怎樣訪問它以及何時訪問它。簡單的說就是對唯一執行個體的受控訪問。  /// <summary> /// 定義一個GetInstance操作,允許客戶訪問他的唯一執行個體,GetInstance是一個靜態方法 /// 主要負責建立自己的唯一執行個體 /// </summary> class Singleton

Stream篇(五)

簡單介紹一下MemoryStreamMemoryStream是記憶體流,為系統記憶體提供讀寫操作,由於MemoryStream是通過無符號位元組數組組成的,可以說MemoryStream的效能可以算比較出色,所以它擔當起了一些其他流進行資料交換時的中間工作,同時可降低應用程式中對臨時緩衝區和臨時檔案的需要,其實MemoryStream的重要性不亞於FileStream,在很多場合我們必須使用它來提高效能 MemoryStream和FileStream的區別前文中也提到了,FileStream主要

302. BHTML 1.0

DescriptionThe hypertext markup language BHTML 1.0 has only two paired tags. They are UP/UP and DOWN/DOWN. The UP/UP tag capitalizes all letters inside its body (between an open tag and a close one), andDOWN/DOWN makes all inside the body letters

poj 1149 PIGS 最大流建圖

/*顧客的先後順序影響銷售把顧客也看成源點和匯點以外的點1 源點和每個豬圈的第一個顧客連邊,邊權為此豬圈豬的數目存在多個豬圈的第一個顧客相同時,只需把邊權相加即可2 對於顧客i,緊鄰他前面有x開啟過同一個房間,連一條邊權無限的邊(可以根據j的需求調度豬)3 每個顧客和匯點連邊,邊權為該顧客的需求*/#include <cstdio>#include <iostream>#include<queue>#include<set>#include<

com.google.common.collect.ImmutableSet

com.google.common.collect Class ImmutableSet<E>java.lang.Object com.google.common.collect.ImmutableCollection<E> com.google.common.collect.ImmutableSet<E>All Implemented

10305 – Ordering Tasks

描述:完全是劉汝佳書上的拓撲排序,一點都沒有變化,不過可能測試範例的輸出與自己測試輸出不一樣,不過沒有事,只要滿足一種合格輸出就可以#include <iostream>#include <cstdio>#include <cstring>using namespace std;int flag,n,m;int topo[110],num[110],s[110][110];bool dfs(int site){ num[site]=-1; for(

Azkaban源碼閱讀之AzkabanApplication

Azkaban是一個Hadoop批處理調度器,可以通過訪問其前台展示頁面來進行部署、運行job等操作。//IndexServlet.java @Override protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException { /* set runtime properties from

Azkaban源碼閱讀之CachingFlowManager

CachingFlowManager這部分為Azkaban在管理job中cache管理這一部分。 public CachingFlowManager(FlowManager baseManager, final int cacheSize) { this.baseManager = baseManager; this.flowCache = Collections.synchronizedMap( new

WPF學習筆記–xaml介紹

 XAML實現UI代碼和應用程式邏輯代碼的分離。在.NET

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