QT小小細節注意點

◆ 安裝 Qt 以後要記得配置環境變數。在 Windows 下安裝以後,用 Qt Command Prompt 可以自動設定,但是要小心幹擾到其他程式的環境變數。較謹慎的辦法是自行開啟 bat 檔案查看所需操作,手動編輯環境變數。◆ Qt Creator 介面上有許多文字沒有設定字型,使用了系統的某個預設配置,導致滿眼都是醜陋的宋體英文。在註冊表的 HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows

網路編程中的逾時檢測

http://www.embedu.org/Column/Column208.htm作者:曾宏安,華清遠見嵌入式學院講師。我們在網路編程中常見的一種做法是:建立好通訊端後以阻塞的方式讀寫,如果沒有資料可讀的話,程式會一直等待。事實上,網路狀況一直不斷變化,很有可能在通訊過程中出現網路連接斷開。我們在程式中有必要對這種情況進行檢測,從而及時做出響應。下面介紹幾種常用的逾時檢測方法(假設我們要求通過通訊端等待資料的最大時間為8秒):一、

poj2155 樹狀數組 Matrix

MatrixTime Limit: 3000MS Memory Limit: 65536KTotal Submissions: 14826 Accepted: 5583DescriptionGiven an N*N matrix A, whose elements are either 0 or 1. A[i, j] means the number in the i-th row and j-th column. Initially we have A[i, j] = 0 (1 <=

matplotlib show() 立即返回,無效,no module named _backend_gdk

具體什麼原因我也不是很清楚,但是可以使用如下方法解決,即在檔案頭部加兩行 import matplotlibmatploblit.use('WXAgg')  或者,修改matplotlib的設定檔,一般位於/usr/local/lib/python2.7/dist-packages/matplotlib/mpl-data/matplotlibrc,修改如下backend: WXAgg如果還是沒用的話,可以嘗試安裝  python-wxtools,sudo apt-get install pyth

Regular Expression Matching LeetCode

這題主要採用遞迴的方式解決,這樣代碼比較容易理解#include <iostream>#include <string>using namespace std;bool isMatch(const char *s, const char *p){if(p[0] == '*')return false;else if(p[0] == 0)return s[0] == 0;else if(p[0] == '.'){if(p[1] == '*'){if(p[2] ==

poj3519 Lucky Coins Sequence矩陣快速冪

Lucky Coins SequenceTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 608 Accepted Submission(s): 319Problem DescriptionAs we all know,every coin has two sides,with one side facing up and another

hdu 3516 四邊形最佳化dp

Tree ConstructionTime Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 689    Accepted Submission(s): 369Problem DescriptionConsider a two-dimensional space with a set of points (xi, yi) that satisfy

有關struct timeval結構體 以及 gettimeofday()函數

轉載地址:http://blog.chinaunix.net/uid-20548989-id-2533161.html一、struct timeval結構體struct timeval結構體在time.h中的定義為:struct timeval{__time_t tv_sec;        /* Seconds.*/__suseconds_t tv_usec;  /* Microseconds.*/};其中,tv_sec為Epoch到建立struct

hdu 4488 Faulhaber’s Triangle

Faulhaber’s TriangleTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 152 Accepted Submission(s): 74Problem DescriptionThe sum of the mth powers of the first n integersS(n,m) = SUM ( j= 1 to n)(

hdu4331 Image Recognition

Image RecognitionTime Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 964    Accepted Submission(s): 371Problem DescriptionNow there is an image recognition problem for you. Now you are given an

hdu3401 Trade 單調隊列最佳化dp

TradeTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2918    Accepted Submission(s): 930Problem DescriptionRecently, lxhgww is addicted to stock, he finds some regular patterns after a few days'

poj3020 最大二分匹配

Antenna PlacementTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 5486 Accepted: 2743DescriptionThe Global Aerial Research Centre has been allotted the task of building the fifth generation of mobile phone nets in Sweden. The most striking

hdu4569 Special equations

Special equationsTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 184 Accepted Submission(s): 92Special JudgeProblem Description  Let f(x) = anxn +...+ a1x +a0, in which ai (0 <= i <= n) are

hdu4105  Electric wave

Electric waveTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 596 Accepted Submission(s): 173Problem DescriptionAli was doing a physic experiment which requires him to observe an electric wave. He

Codeforces Round #196 (Div. 2) B. Routine Problem

B. Routine Problemtime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard outputManao has a monitor. The screen of the monitor has horizontal to vertical length ratio a:b. Now he is going to watch a movie. The

hdu4336 Card Collector 狀態壓縮dp

Card CollectorTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1708 Accepted Submission(s): 780Special JudgeProblem DescriptionIn your childhood, do you crazy for collecting the beautiful cards in

有感而寫

       從大三到現在,出來校門整整一年了,最近覺得很浮躁,不知道該去做什麼,該怎麼去做,畢業了,離開那個墮落的天堂---大學,突然覺得俺學校挺好的,以往的抱怨煙消雲散。     

sigaction函數解析

sigaction函數的功能是檢查或修改與指定訊號相關聯的處理動作(可同時兩種操作)。他是POSIX的訊號介面,而signal()是標準C的訊號介面(如果程式必須在非POSIX系統上運行,那麼就應該使用這個介面)給訊號signum設定新的訊號處理函數act, 同時保留該訊號原有的訊號處理函數oldactintsigaction(int signo,conststruct sigaction*restrict act,             struct sigaction*restrict

hdu4486 Pen Counts

Pen CountsTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 205 Accepted Submission(s): 112Problem DescriptionChicken farmer Xiaoyan is getting three new chickens, Lucy, Charlie and CC. She wants to

hdu4489 The King’s Ups and Downs

The King’s Ups and DownsTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 163 Accepted Submission(s): 101Problem DescriptionThe king has guards of all different heights. Rather than line them up in

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