UVa Problem Solution: 10077 – The Stern-Brocot Number System

Just like find a number in a binary search tree. The only trick is keeping record of the current node's left and right node to get to its child node.Code:/************************************************************************* * Copyright (C) 2008 

UVa Problem Solution: 10038 – Jolly Jumpers

Simple problem. Just record the absolute values of the differences will do the job.Code:/************************************************************************* * Copyright (C) 2008 by liukaipeng                                      * * liukaipeng 

UVa Problem Solution: 10050 – Hartals

At the first look, the hartals can be counted with the principle of inclusion and exclusion. However, this may cause the calculations to expand to O(2^numberof(parties)). In another way, simply simulation will also do the job.Code:/******************

uva 658

問題描述:不說了,。。。解法:dijkstra+state represented by binary codenotes: if a state must meet "**1**1**"  <=>  (state | "00100100")==state            and if a state must meet "**0**0**" <=> (state & “11011011” ==state)            so if you

qemu-kvm 建立ubuntu 虛擬機器

qemu 和 kvm 的關係KVM 是指基於 Linux 核心的虛擬機器(Kernel-based Virtual Machine)。 2006 年 10 月,由以色列的 Qumranet 組織開發的一種新的“虛擬機器”實現方案。 2007 年 2 月發布的 Linux 2.6.20 核心第一次包含了 KVM 。增加 KVM 到 Linux 核心是 Linux 發展的一個重要裡程碑,這也是第一個整合到 Linux

uva 10369

問題描述,尋找一條可以運載最多客人的巴士路徑,求最優解解法:dijkstra,#include<cstdio>#include<cstring>#include<cstdlib>#include<cmath>#include<queue>#define INF 200000000using namespace std;typedef pair<int ,int > pii;const int maxn=105;int

貝葉斯文本分類實驗

這個其實是我資料採礦 的大作業 :實驗原理主要是利用樸素貝葉斯對文本進行分類,用TF-IDF 權重進行最佳化。實驗流程:1 首先下載搜狗語料庫採用其中的五個類別,分別是,1 – 汽車2 –財經3 — 教育 IT4 — 健康5 — 體育 。其中每個分類的訓練文檔為1000篇,測試文檔為131篇。2中文分詞利用中科院的分詞軟體,對所有的文檔進行分詞。比如 第一個類別下的 10.txt 分詞後的結果儲存在1_re_10.txt 中 。 分詞結果(只列出部分):/x /x 本報/rz 記者/n

UVa Problem Solution: 10082 – WERTYU

The simplest problem ever since...Code:/************************************************************************* * Copyright (C) 2008 by liukaipeng                                      * * liukaipeng at gmail dot com                                 

微軟的一道面試題

有12個大小相同的乒乓球,其中只有一個的重量和其他的不同,要求用一台沒有砝碼的天平稱三次找出這個重量不同的球!  一個偶然的機會一位仁兄問我這樣的問題,當時我以為那個球是重的(以前曾做過一道類似的,慣性思維),以為很簡單,後來細想才知道是有難度的,而晚上睡覺簽發了半小時也沒有想通,那天睡覺是伴隨著這個問題進入夢鄉的,還好第二天想出了。大致如下:將球編號 1 2 3 4 5 6 7 8 9 10 11 12 ;分成三組 ;先 1234 與 5678 稱 1 要是相等的話:    

北大ACM題庫習題分類與簡介

北大ACM題庫習題分類與簡介zz題目分類Posted by fishhead at 2007-01-13 12:44:58.0 --------------------------------------------------------------------------------acm.pku.edu.cn1、   排序1423, 1694, 1723, 1727, 1763, 1788, 1828, 1838, 1840, 2201, 2376, 2377, 2380, 1318, 1

Monitoring Clusters With SNMP

MONITORING theperformance of hosts in your cluster is somewhat a boring task. I'veseen various programs written to access system usage informations withhandmade methods, such as filtering output of commands, or readingfields from files in the '/proc'

UVa Problem Solution: 847 – A Multiplication Game

We can easily observe that if the drawn number is in range [2, 9], Stan will win, and if it is in range [10, 18], Ollie will win. Suppose that one of Span's win range is [m, n], it can be extend to the next win range of [2*m+1, 2*9*n)]. Thus, the

uva 515 || poj 1364

問題描述:給出ai,ni,op字串(分別表示>和<),ci,表示S(ai)+S(ai+1)+....+S(ai+ni)>/<ci問是否存在這樣的S問題解法:差分約束,超杯具,我竟然把S(ai)+S(ai+1)+....+S(ai+ni)表示成S(ai+ni)-S[ai],很明顯這是錯的,應該是:S(i)表示i之前(不含i)的連續和,所以上式應表示成S(ai+ni+1)-S(ai)另外由於本題是嚴格的<

uva 558

問題描述:給出一個含負權的圖,判斷是否存在負圈,bellman ford

UVa Problem Solution: 10105 – Polynomial Coefficients

The coefficient of x1n1x2n2...xknk is (n, n1)(n-n1, n2)...(n-n1-n2-...-nk-1, nk) = n!/n1!n2!...nk!.Code:/************************************************************************* * Copyright (C) 2008 by liukaipeng                                     

UVa Problem Solution: 10205 – Stack ‘em Up

Simple simulation will do the job.Code:/************************************************************************* * Copyright (C) 2008 by liukaipeng                                      * * liukaipeng at gmail dot com                                 

uva 10465

問題描述:給出m,n,t,m表示吃第一種食物的時間,n為第二種的時間,t,為總時間,如果能將t全部用於吃的,那麼就輸出食物數量的最大值,否則在剩餘時間喝啤酒,輸出使喝啤酒的時間最小時的食物數量的最大值,以及喝啤酒的時間,(有點拗口,慢慢體會)解法:完全背包。。。超簡單的題目,做了一個多鐘。。。。原因:一直沒理解好題目,原來問的是啤酒的時間最小時的食物數量的最大值,以及喝啤酒的時間,而不是食物數量最大時的喝啤酒時間的最小值。。。總結:一定要好好看題,理解題目。。。有歧義的時候,寧可慢也不可誤會。。

UVa Problem Solution: 10010 – Where’s Waldorf

I use the naive string search method that scans for the eight directions at each point in the matrix. Due to the relatively small input size, this method work well enough to get the top 20% ranking.Code:/**********************************************

UVa Problem Solution: 10252 – Common Permutation

Really simple problem. However, two points need to be considered:1. ... find the largest string x such that there is a permutation of x that is a (not necessarily continuous) subsequence of a ...2. if there are spaces in the input, ignore them in

UVa Problem Solution: 10188 – Automated Judge Script

Not a difficult problem. Just catenate the lines together and compare the correct and submitted answer will do it well. Unfortunately, the problem statement is misleading: I get WA consistently with a "linesize" of 102, however, it becomes AC when I

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