標籤:如果我要取11-20的Students表的資料,則為: Select * From Students Limit 9 Offset 10;表示從Students 表擷取資料,跳過10行,取9行 。也可以這樣寫 select * from Students limit 10,9 和上面的的效果一樣。 通用公試: sql = "select * from TableName where "+條件+" order by "+排序+"
標籤:在連sqlite資料庫時,用fetchall()查詢結果,是用row[0],row[1]這樣的方式來列印每列的結果但是我想用row[“欄位名”]方式查詢怎麼辦?import sqlite3con = sqlite3.connect("mydb")con.row_factory = sqlite3.Rowcur = con.cursor()cur.execute("select name_last, age from people")for row in cur:
標籤:昨天被ionic和sqlite折騰一天,怎麼也無法實現讀取,後來才發現,原來是codova中的sqliteplugin版本問題。問題:Database location or iosDatabaseLocation value is now mandatory in openDatabase call, http://172.20.10.5:8100/plugins/cordova-sqlite-storage/www/SQLitePlugin.js, Line:
標籤:1查詢Student表中的所有記錄的Sname、Ssex和Class列。SELECT sname,ssex,class from Student2查詢教師所有的單位即不重複的Depart列。SELECT Depart from Teachear3查詢Student表的所有記錄。SELECT * from Student4查詢Score表中成績在60到80之間的所有記錄。SELECT degree from Score where Degree>60 and Degree<805
標籤: string sqlstring = "select * from endpoint_policy where HEX([UserGuid]) =‘" + CommonHelper.ConvertGuid(uguid) + "‘"; var query = db.Database.SqlQuery<endpoint_policy>(sqlstring).AsQueryable(); var endpoint_policy = new