A Java function implements any given set of numbers, finding that the result of any number added is 35.

Source: Internet
Author: User
Tags arrays

Write a function in Java. The function is as follows: Any given set of numbers, such as {12,60,-8,99,15,35,17,18}, to find out the result of the addition of any number 35 (arbitrary set).

can be recursive algorithm to solve:

Package test1;
    
Import Java.util.Arrays; public class Demo {public static void main (string[] args) {String str = ' 12,60,-8,99,15,35,17,18,8,
        10,11,12 ";
        int sum = 35;
    Diguisum (str,sum);
        public static void Diguisum (String str,int sum) {string[] x = Str.split (",");
        int[] Array = arraytransform (x);
            for (int i = 0; i < Array.Length i++) {int[] cache = new Int[i + 1];
            int ceng =-1;
            int cengquit = i;
            int startpiont = 0;
        Cir (CEng, cengquit, Startpiont, array, cache, sum);  }///recursive results public static void Cir (int ceng, int cengquit, int startpiont, int[] array, int[] cache, int
        sum) {ceng++;
            for (int i = Startpiont i < array.length; i++) {Cache[ceng] = Array[i];
   if (CEng = = Cengquit) {if (getsum (cache) = sum) {Printcache (cache);             } if (Getsum (cache) > sum) {break;
                } if (CEng < cengquit) {Startpiont = i + 1;
            Cir (CEng, cengquit, Startpiont, array, cache,sum);
        }}//Get combined number and public static int getsum (int[] cache) {int sum = 0;
        for (int i = 0; i < cache.length i++) {sum = sum + cache[i];
    return sum; 
            The possible public static void Printcache (int[] cache) of the//print combination is {for (int i = 0; i < cache.length; i++) {
        System.out.print (Cache[i] + ",");
    } System.out.println ();
    
        }//convert array type and prepare for increased efficiency public static int[] Arraytransform (string[] strarray) {int length = 0;
        int[] array = new Int[strarray.length];
        for (int i = 0; i < strarray.length i++) {Array[i] = integer.valueof (strarray[i));
    }    Arrays.sort (array);
                for (int i = 0; i < Array.Length i++) {if (Array[i] >) {length = i;
            Break
        } int[] Dest = new Int[length];
        System.arraycopy (array, 0, dest, 0, length);
    return dest; }
}

This algorithm is suitable for reference.

Run Result:

See more highlights of this column: http://www.bianceng.cnhttp://www.bianceng.cn/Programming/Java/

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