Basic Practice Letter GraphicTime limit: 1.0s memory Limit: 256.0MB problem description
Using letters to make up some beautiful graphics, here's an example:
ABCDEFG
Babcdef
Cbabcde
Dcbabcd
Edcbabc
This is a 5 row 7 column of graphics, please find out the pattern of this graph, and output a n row m column of graphics. Enter a line that contains two integers n and m, representing the number of rows of the graph you want to output, respectively. Output format output n rows, each m character, for your graphics. Example Input 5 7 sample output ABCDEFG
Babcdef
Cbabcde
Dcbabcd
EDCBABC Data size and convention 1 <= N, M <= 26.
Topic Link: http://lx.lanqiao.cn/problem.page?gpid=T7
Idea: The number of letters is related to the absolute value of the difference of two coordinates. Use the double loop to enumerate all the coordinates, use the absolute value function to calculate the difference of the coordinates, and then output the corresponding characters. (Pay attention to finding the rules from the point of view of coordinates)
The code is as follows:
Import java.util.*;
public class Main {public
static void Main (string[] args) {
char c[] = {' A ', ' B ', ' C ', ' D ', ' E ', ' F ', ' G ', ' H ', ' I ', ' J ', ' K ', ' L ', ' M ', ' N ', ' O ', ' P ', ' Q ', ' R ', ' S ', ' T ', ' U ', ' V ', ' W ', ' X ', ' Y ', ' Z '};
Scanner sc = new Scanner (system.in);
int n = sc.nextint ();
int m = Sc.nextint ();
for (int i=0;i<n;i++) {for
(int j=0;j<m;j++) {
int x = Math.Abs (i-j);
System.out.print (C[x]);
System.out.println ();}}