Competition--Arranging the garden problem--solving report

Arranging garden problems

Main topic:

There are three families with a garden, and the wives of each family are required to help arrange the garden. Mrs. A worked for 5 days, and Mrs. B worked for 4 days before finishing the garden. Mrs. C was 90 yuan because she was pregnant unable to join them. How is this money assigned to a and B two wives more appropriate? How many dollars does A deserve? 90/(5+4) *5=$50 yuan? If you think so, you'll be fooled! The correct answer is 60 yuan. If you don't get it, think again. Here's a general question: Suppose Mrs. A worked for x days, Mrs. B worked for y days, and Mrs. C paid $90, how much does Mrs. a deserve? The input guarantees that two wives should be given non-negative integer dollars. Three wives work the same. Friendship Hint: there is a small trap in the subject. If the answer is wrong, please check the code carefully. Requirements:InputEnter the number of first behavior Data group T (T<=20). Only one row per group of data, containing three integers x, y, Z (1<=x, y<=10,1<=z<=1000). Output for each set of data, output an integer, that is, the amount that Mrs. a deserves (unit: yuan). Sample input: Sample Input

Sample Output

Note the prompt:
If using floating-point numbers, be careful about the error, and use rounding as much as possible when outputting.

Topic Analysis:
This is a typical mathematical problem. The first thing to do is to make a formula, to find the formula and write the program is simple. To get the money from Mrs. A, because the floating-point number is the problem, the formula is calculated according to the calculation
Three people do each should do the number of days s= (X+Y)/3.0; A more days to do a=x-s; b More days to do b=y-s; c should be paid a pay=a/(a+b) *z.
Program code:

1#include <cstdio>2#include <iostream>3 using namespacestd;4 5 intt[ -];6 inty[Ten];7 intz[ +];8 9 intMain ()Ten { One     intT; Ascanf"%d",&T); -      while(t--) -     { the     intx, y, z -     DoubleA,b,s,pay; -      -      +scanf"%d%d%d",&x,&y,&z); -      +s= (x+y)/3.0;//Three people do the number of days each should do AA=x-s;//a more days to do atB=y-s;//b More days to do -pay=a/(a+b) *z;//c The amount of money payable to a -         intk=pay+0.5;//rounding up the money to get an integer -cout<<k<<Endl; -     } -     return 0; in      -}

Experience:
This problem seems simple, but it is in the calculation of a should get how much money, always can not find the relationship, so calculated for a long time. After the relationship is found, the program will be finished soon. It's a very simple question.

Feel that they have some problems in thinking, the next time you should do more math problems, exercise their own thinking ability.

Competition--Arranging the garden problem--solving report