Java input numbers are stored in an array (with character detection)

This time is an enhanced version of whether the last character detection is all digital.

You are welcome to point out the shortcomings of friends or the great God.

 Packagecom.hw.h817;ImportJava.util.Scanner; Public classCheck {public static void main (string[] args){Scanner s=NewScanner (system.in); //define the pre and STR outside, if the definition in the loop goes wrongString[] both =NewString[6];        String Pre; int[] str =New int[6]; intCount = 0;//used to exit a loop                 while(true) {System.out.println ("Please enter 6 numbers in turn"); Count= 0;//if the input character is not a number, it is counted back from if             for(inti=0;i<6;i++) {Pre= S.next ();//Receive String                if(! (Pre.matches ("\\d+"))) {//non (pre is all numbers)SYSTEM.OUT.PRINTLN ("Input + pre +" is not a number, please re-enter ");  Break;//this exits the for loop, and then executes the while loop again, re-entering the number                }                Else{Str[i]= Integer.parseint (pre);//converts a numeric string to an int type number} Count++;//count will only be +1 after each data entry is performed            }            if(count==6) Break;//This exit is the while loop.        }         for(inti=0;i<6;i++) {//Output Print Numbers            if(i==0) {System.out.print (str[i]); }            Else{System.out.print (","+Str[i]); }        }    }}

Java input numbers are stored in an array (with character detection)