Python initializes multidimensional array code _python

The best way to initialize an array of 5 x 3 per 0 in Python is to:

Multilist = [[0 for Col in range (5)] for row in range (3)]< /c15>

We know that in order to initialize a one-dimensional array, we can do this:

Alist = [0] * 5

Yes, so when we initialize a two-dimensional array, can we do this:

Multi = [[0] * 5] * 3

In fact, this is wrong, because [0] * 5 is a one-dimensional array of objects, * 3 words just copy the object's Reference 3 times, for example, I modify multi[0][0]:

Multi = [[0] * 5] * 3
Multi[0][0] = ' love of the '
Print Multi

The results of the output will be:
[[' Love of the ', 0, 0, 0, 0], [' Love of the ', 0, 0, 0, 0], [' Love ', 0, 0, 0, 0]]
We have modified multi[0][0], but we have changed our multi[1][0],multi[2][0. This is not the result we want.

What if we write this:

Multilist = [[0] * 5 for row in range (3)]
Multilist[0][0] = ' love of the '
Print multilist

Let's see the output:
[[' Love of the ', 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0]]
Yes, no problem. However, because the method of using * is more likely to cause confusion resulting in bugs, it is recommended that the first method above be used, namely:

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--> multilist  =  [[0  for  col   in  range ( 5 )] , for  row , in  range ( 3 )]