Huawei 2015 Simple Dictionary Input Method java

Topics excerpted from http://blog.csdn.net/dongyi91/article/details/38639915 wrote for 2 hours, level too dish out

The encoding principle of the method is: according to the existing code table, when the input pinyin and the number of characters after the output. For example:

There is the following code: XI _xi Wash _xi system _xi no _WU five _wu (between the characters and pinyin separated by an underscore), then when the input xi2, the result is the second character of the phonetic bit XI, namely "wash".

Input: Code

Hi _xi

Wash _xi

Department _xi

No _wu

Five _wu

Search

Xi2

End

Output: Wash

Note: When the query is not in the encoding table, the result is "Error"; when the input pinyin does not have a number, that is, "Xi", the output is: Pinyin is the first number of Xi's characters, but the maximum output of 5, that is, the output: HI; wash; department.

Research points: String segmentation, String conversion to integer type, Multimap use (key is pinyin, value is the corresponding character).

Package Huawei Machine test; import java.util.arraylist;import java.util.hashmap;import java.util.iterator;import Java.util.Scanner ;p Ublic class Main4 {public static void main (string[] args) {//TODO auto-generated method Stubscanner scn=new Scanner (Sys tem.in);//Read codehashmap<string,arraylist<string>> hash=new hashmap<string,arraylist<string>    > ();         String Cur=scn.next ();        while (!cur.equals ("Search")) {String S[]=cur.split ("_");      System.out.println (s[0]+ "--" +s[1]);          if (Hash.get (s[1]) ==null) {ArrayList arry=new arraylist<string> ();          Arry.add (S[0]);                     Hash.put (S[1],arry);                  } else {hash.get (s[1]). Add (S[0]);         } cur=scn.next ();         }//Output hash value/* iterator<string> iter=hash.keyset (). Iterator ();         while (Iter.hasnext ()) {System.out.println (Iter.next ());       }         */  Cur=scn.next ();        while (!cur.equals ("End")) {char Last=cur.charat (cur.length ()-1);        System.out.println ("cur" + last);        Separate the number of words if (last>= ' 0 ' &&last<= ' 9 ')///The last one is whether there are numbers {int i;        For (I=0;i<cur.length (); i++) {char c=cur.charat (i);                if (c> ' 0 ' &&c<= ' 9 ') break;        } String key=cur.substring (0,i);                int pos=integer.valueof (cur.substring (i));        if (Hash.get (key) ==null) System.out.println ("Error");        else {System.out.println (Hash.get (key). Get (POS));        }} else//not the number directly outputs the first 5, if any, {int count=0;        For (String s:hash.get (cur)) {System.out.println (s);        count++;        if (count==5) break;                  }} cur=scn.next (); }}}

　　

Huawei 2015 Simple Dictionary Input Method java