It's not that simple: how to determine whether an integer is an even or an odd number in Java

Environment: JDK 1.7.

Package Hellojava; public class Hellojava {//Use remainder operation public boolean isEven01 (int num) {if (num% 2 = = 0) {return t        Rue        } else {return false;        }}//If there is no take-up operator, make a public boolean isEven02 (int num) {int tmp = NUM/2;        if (num-tmp*2 = = 0) {return true;        } else {return false;        }}///Change the idea of public boolean isEven03 (int num) {String numstr = new Integer (num). toString ();                 Char Lastchar = Numstr.charat (Numstr.length ()-1); Switch (Lastchar) {case ' 0 ': Case ' 2 ': Case ' 4 ': Case ' 6 ': Case ' 8 ' : Return true;             There's no need to break. Default:return false;        }} public static void Main (string[] args) {Hellojava HJ = new Hellojava ();        System.out.println (Hj.iseven01 (10));        System.out.println (HJ.ISEVEN02 (10)); SYstem.out.println (HJ.ISEVEN03 (10));        System.out.println (Hj.iseven01 (11));        System.out.println (HJ.ISEVEN02 (11));     System.out.println (HJ.ISEVEN03 (11)); } }

Execution Result:

truetruetruefalsefalsefalse

In addition, the minus 2 and the remainder of the negative integer should be noted:

package hellojava; public class HelloJava {         public static void main(String[] args) {                 System.out.println(-10/2);        System.out.println(-10%2);        System.out.println(-11/2);        System.out.println(-11%2);    } }

The results of the operation are as follows:

-50-5-1

It's not that simple: how to determine whether an integer is an even or an odd number in Java