JavaScript operators apply

What does the following code output? Why?

Console.log (1 + "2" + "2"), Console.log (1 + + "2" + "2"), Console.log (1 +-"1" + "2"), Console.log (+ "1" + "1" + "2"); CONSOLE.L OG ("A"-"B" + "2"); Console.log ("A"-"B" + 2);

The results were

122,32,02,112,nan2,nan

The second and third questions are to be noted here.

The second question of the + "2" result is to convert the string 2 into the number 2, the result is a string 32

The third question-the result of "2" is to convert the string 2 into the number 2, resulting in a string of 02

The +,-operator acts as a transform here, converting a string to a computable expression, which is useful for writing self-executing functions.

(function () {}) ()  //Return Undefined+function () {} ()   //Return Nan-function () {} ()   //Return Nan!function () {} ()   //Return true~ function () {} ()   //Return-1

These can act as self-executing, but the return value is different.

JavaScript operators apply