Jump between IOS Apps

Jump from one appclient to another appserver, where the appclient appserver knowledge represents two different apps and does not have bunldid functionality. I got the wrong idea at first.

The implementation jumps from Appclient to another appserver:

1. First add a line attribute to AppServer's info.plist.

The URL is composed of: Pupuwang://com.pupuwang.xwcustomer

Where URL schemes is most important, is the prefix of the URL, url identifier is URL://String after

2. In AppServer's uiapplication agent, the implementation

-(BOOL) Application: (UIApplication *) application OpenURL: (nsurl *) URL sourceapplication: (NSString *) sourceapplication annotation: (ID) annotation{    if ([[url absolutestring] Iscontainsubstring:@ "com.pupuwang.XWCustomer"]) {        return  YES;    }     return NO;}

3. In the Appclient

Nsurl *url = [Nsurl urlwithstring:@"Pupuwang://com.pupuwang.xwcustomer"];//URL pattern: appserver URL schemes://url identifierbool hasinstagram=[[UIApplication sharedapplication] canopenurl:url];if(hasinstagram) {//Jump[[UIApplication sharedapplication] openurl:url];}Else{    //Download to AppStore//nsstring *url = [NSString stringwithformat:@]https://itunes.apple.com/cn/app/id%@ ", xw_b_appid];NSString *url = [NSString stringWithFormat:@"https://itunes.apple.com/"]; UIApplication* Application =[UIApplication sharedapplication]; //Download the Merchant edition to the store[Application Openurl:[nsurl urlwithstring:url];}

and implement UIApplication's agent

-(BOOL) Application: (UIApplication *) application Handleopenurl: (Nsurl *) url{    return  YES;

You can jump from appclient to AppServer

Jump between IOS Apps