NumPy the determinant of an array in Python Numpy.linalg.det ()

Numpy.linalg.det

numpy.linalg.det(a)[source]

Computes the determinant of any array a, but this requires that the last two dimensions of the array must be square.

Parameters:	a : (....., M, m) array_like Input array to compute determinants for.
Return:	det : (...) Array_like Determinant of a.

For example:

1>>>a=np.reshape (Np.arange (6), (2,3))2>>>a3Out:array ([[[0, 1, 2],4[3, 4, 5]])5>>>Np.linalg.det (a)6Out:LinAlgError:Last 2dimensions of the array must be square7 8>>>a=np.reshape (Np.arange (20), (5,2,2))9>>>aTenOut:array ([[[[[0], 1], One[2, 3]], A  -[[4, 5], -[6, 7]], the  -[[8, 9], -[10, 11]], -  +[[12, 13], -[14, 15]], +  A[[16, 17], at[18, 19]]]) -  ->>>Np.linalg.det (a) -Out:array ([-2.,-2.,-2.,-2.,-2.])

In fact, this function is to calculate the determinant value of a square matrix.

NumPy the determinant of an array in Python Numpy.linalg.det ()