Python jumps out for loop continue and break program

Use for statement
Example 6.3 uses a for statement

The code is as follows	Copy Code
#!/usr/bin/python # Filename:for.py For I in range (1, 5): Print I Else print ' For loop are over ' Output $ python for.py 1 2 3 4 The For loop are over

Jump out for Loop

Continue

The code is as follows	Copy Code
# Encoding=utf-8 For x in range (10): If x==5: Continue Print X

The above loop uses continue to jump out of this cycle, so only when the x==5 out of this cycle, and then continue next, so the print X statement only in the x==5 when the other values are executed to the

Break

The code is as follows	Copy Code
# Encoding=utf-8 For x in range (10): If x==5: Break Print X

The break loop used above, so the entire for loop is jumped out of the x==5, so the print X statement terminates only when it hits 4.

Other instances

# First: Ask for prime numbers between 50-100

The code is as follows	Copy Code
Import Math For I in range (50, 100 + 1): For j in range (2, int (math.sqrt (i)) + 1): If I% j = 0: Break Else Print I

# Second: Put else's position in the same indent as if.

The code is as follows	Copy Code
Import Math For I in range (50, 100 + 1): For j in range (2, int (math.sqrt (i)) + 1): If I% j = 0: Break Else Print I

# Third: Add a break statement after else.

code is as follows	copy code
Import Math for I in range (1):     to J in range (2, int (math.sqrt (i)) + 1):    & nbsp;    if I% j = 0:             break         Else:              print I             break